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We can draw the figure with the given details.

Let A be the window of the house, B be the base of the house and C be the foot of the ladder. This forms a right-angled triangle.

It is given that length of ladder is ${\text{10m}}$. So, ${\text{AC = 10m}}$.

The window is ${\text{8m}}$high. So ${\text{AB = 8m}}$.

We need to find the distance of the foot of the ladder from the base of the wall.

Consider the right triangle ABC. According to Pythagoras theorem, for a right-angled triangle,

${\text{A}}{{\text{B}}^{\text{2}}}{\text{ + B}}{{\text{C}}^{\text{2}}}{\text{ = A}}{{\text{C}}^{\text{2}}}$

Substituting the values of AB and AC in the equations, we get,

${{\text{8}}^{\text{2}}}{\text{ + B}}{{\text{C}}^{\text{2}}}{\text{ = 1}}{{\text{0}}^{\text{2}}}$

Subtracting both sides with ${{\text{8}}^{\text{2}}}$, we get,

${\text{B}}{{\text{C}}^{\text{2}}}{\text{ = 1}}{{\text{0}}^{\text{2}}}{\text{ - }}{{\text{8}}^{\text{2}}}$

Taking the squares and simplifying, we get,

${\text{B}}{{\text{C}}^{\text{2}}}{\text{ = 100 - 64 = 36}}$

Taking the square root, we get,

${\text{BC = }}\sqrt {{\text{36}}} {\text{ =6}}$

As we are taking the distance, we only take the positive value.

$ \Rightarrow {\text{BC = 6m}}$

Therefore,