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Now we have a labourer earn \[Rs.{\rm{ 1980}}\] in \[12\] days.

By the unitary method first we have to find quantity of single unit value

Therefore, now we are going to find a labourer who earns money for one day. Dividing earned money \[Rs.{\rm{ 1980}}\] by the number of days to earn that money. It is \[12\] days.

Hence,

\[\Rightarrow {\rm{ }}\dfrac{{1980}}{{12}}\]

Cancelling the numerator and denominator by \[4\] we get,

\[ \Rightarrow {\rm{ }}\dfrac{{1980}}{{12}} = \dfrac{{495}}{3}\]

Cancelling the numerator and denominator by \[3\] we get,

\[ \Rightarrow {\rm{ }}\dfrac{{495}}{3} = \dfrac{{165}}{1} = Rs.{\rm{ }}165\]

Therefore a labourer earns \[Rs.{\rm{ }}165\] in one day.

Again using the unitary method we have to multiply the single unit value into our required value.

Now we have to find how many days a labourer takes to earn \[Rs.{\rm{ 2640}}\].

Hence we have to divide\[Rs.{\rm{ 2640}}\]by\[Rs.{\rm{ }}165\]that is the amount earned by the person in a day.

\[ \Rightarrow {\rm{ }}\dfrac{{2640}}{{{\rm{165}}}}\]

\[ \Rightarrow {\rm{ 16}}\]

Now we find \[{\rm{16}}\] days takes a labourer to earn \[Rs.{\rm{ 2640}}\].