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Curved Surface Area: The area of the curved surface of the cylinder which is contained between the two parallel circular bases. It is also stated as a lateral surface area. The formula for it is given by:

\[{\text{surface area of cylinder = 2}}\pi {\text{rh}}\]

First of all we will find the area of the curved surface:

\[{\text{Rs }}0.{\text{2}}0{\text{ = 1}}00cm{.^2}\]

\[{\text{Rs 1 }} = {\text{ }}\dfrac{{100}}{{0.2}} = {\text{ 5}}00c{m^2}\]

\[{\text{Rs 352 }} = {\text{ 5}}00{\text{ x 352 }} = {\text{ 176}}000c{m^2}\]

Then we will find the radius:

\[{\text{Radius }} = {\text{ }}\dfrac{{{\text{Diameter}}}}{2}\]

\[{\text{Radius }} = {\text{ }}\dfrac{{56}}{2} = 28cm\]

then we will find the height:

\[{\text{Curved surface area }} = {\text{ 2}}\pi h\]

Given that area = \[\,{\text{176}}00c{m^2}\] and the radius = \[{\text{2}}cm.\]

\[{\text{2}}\pi \left( {{\text{28}}} \right)h{\text{ }} = {\text{ 176}}000\]

\[{\text{56}}\pi h{\text{ }} = {\text{ 176}}000\]

\[h = {\text{ }}\dfrac{{{\text{176}}000}}{{56\pi }}\]

\[h = {\text{1}}000{\text{ cm or 1}}0{\text{m}}\]

Hence, the height is \[{\text{1}}0\]m

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