A chess board contains $64$ equal squares and the area of each square is $6.25c{m^2}$, the border around the square is $2cm$ wide. The length of the chess board is
$
A)\,8cm \\
B)\,24cm \\
C)\,12cm \\
D)\,16cm \\
$
Answer
609.3k+ views
Hint:Since the chess board is a square and it actually consists of $64$ equals square boxes. The side length of each square box can be calculated since its area is given. Also there is a $2cm$ wide border on all the sides of the chess board. So, to calculate the complete length of the board, the length of borders will also be included.
Complete step-by-step answer:
The chess board contains $64$ equal squares. We know that the overall shape of the chess board is also a square.
Therefore, the chess board has $8 \times 8$ small squares.
It is mentioned in the question that the area of each small square is $6.25c{m^2}$.
We know that the area of a square is equal to the square of its side length
${\left( {side} \right)^2} = area$
$side\,length = \sqrt {area} $
$\therefore $ The side length of each of the small squares is equal to the square root of its area
$side = \sqrt {6.25} $
$side = 2.5cm$ $ \to \left( 1 \right)$
Now, it is also given that the chess board has a border in width $2cm$
Therefore, the side length of the whole chess board will be equal to the sum of length of small squares on one side and the width of the border on the two sides.
$Total\,length = 8 \times length\,of\,one\,small\,square + 2 \times width\,of\,the\,\,border$
$Total\,length = 8 \times 2.5 + 2 \times 2$
$Total\,length = 20 + 4 = 24cm$
So, the correct answer is “Option B”.
Note:It should be noted that borders will exist on the both sides when the total length of the chess board is to be considered.Each statement given in the question needs to be understood carefully while converting them in mathematical form.
Complete step-by-step answer:
The chess board contains $64$ equal squares. We know that the overall shape of the chess board is also a square.
Therefore, the chess board has $8 \times 8$ small squares.
It is mentioned in the question that the area of each small square is $6.25c{m^2}$.
We know that the area of a square is equal to the square of its side length
${\left( {side} \right)^2} = area$
$side\,length = \sqrt {area} $
$\therefore $ The side length of each of the small squares is equal to the square root of its area
$side = \sqrt {6.25} $
$side = 2.5cm$ $ \to \left( 1 \right)$
Now, it is also given that the chess board has a border in width $2cm$
Therefore, the side length of the whole chess board will be equal to the sum of length of small squares on one side and the width of the border on the two sides.
$Total\,length = 8 \times length\,of\,one\,small\,square + 2 \times width\,of\,the\,\,border$
$Total\,length = 8 \times 2.5 + 2 \times 2$
$Total\,length = 20 + 4 = 24cm$
So, the correct answer is “Option B”.
Note:It should be noted that borders will exist on the both sides when the total length of the chess board is to be considered.Each statement given in the question needs to be understood carefully while converting them in mathematical form.
Recently Updated Pages
Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Class 10 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
What is the full form of PNG A Petrol Natural Gas B class 10 chemistry CBSE

The power of the lens is 2D What is its focal length class 10 physics CBSE

Distinguish between the reserved forests and protected class 10 biology CBSE

Metals which do not react with dilute acids beginarray20l class 10 chemistry CBSE

If a trait A exists in 10 of a population of an asexually class 10 biology CBSE

Find the value of log sqrt 2 64 class 10 maths CBSE

