
A chess board contains $64$ equal squares and the area of each square is $6.25c{m^2}$, the border around the square is $2cm$ wide. The length of the chess board is
$
A)\,8cm \\
B)\,24cm \\
C)\,12cm \\
D)\,16cm \\
$
Answer
586.5k+ views
Hint:Since the chess board is a square and it actually consists of $64$ equals square boxes. The side length of each square box can be calculated since its area is given. Also there is a $2cm$ wide border on all the sides of the chess board. So, to calculate the complete length of the board, the length of borders will also be included.
Complete step-by-step answer:
The chess board contains $64$ equal squares. We know that the overall shape of the chess board is also a square.
Therefore, the chess board has $8 \times 8$ small squares.
It is mentioned in the question that the area of each small square is $6.25c{m^2}$.
We know that the area of a square is equal to the square of its side length
${\left( {side} \right)^2} = area$
$side\,length = \sqrt {area} $
$\therefore $ The side length of each of the small squares is equal to the square root of its area
$side = \sqrt {6.25} $
$side = 2.5cm$ $ \to \left( 1 \right)$
Now, it is also given that the chess board has a border in width $2cm$
Therefore, the side length of the whole chess board will be equal to the sum of length of small squares on one side and the width of the border on the two sides.
$Total\,length = 8 \times length\,of\,one\,small\,square + 2 \times width\,of\,the\,\,border$
$Total\,length = 8 \times 2.5 + 2 \times 2$
$Total\,length = 20 + 4 = 24cm$
So, the correct answer is “Option B”.
Note:It should be noted that borders will exist on the both sides when the total length of the chess board is to be considered.Each statement given in the question needs to be understood carefully while converting them in mathematical form.
Complete step-by-step answer:
The chess board contains $64$ equal squares. We know that the overall shape of the chess board is also a square.
Therefore, the chess board has $8 \times 8$ small squares.
It is mentioned in the question that the area of each small square is $6.25c{m^2}$.
We know that the area of a square is equal to the square of its side length
${\left( {side} \right)^2} = area$
$side\,length = \sqrt {area} $
$\therefore $ The side length of each of the small squares is equal to the square root of its area
$side = \sqrt {6.25} $
$side = 2.5cm$ $ \to \left( 1 \right)$
Now, it is also given that the chess board has a border in width $2cm$
Therefore, the side length of the whole chess board will be equal to the sum of length of small squares on one side and the width of the border on the two sides.
$Total\,length = 8 \times length\,of\,one\,small\,square + 2 \times width\,of\,the\,\,border$
$Total\,length = 8 \times 2.5 + 2 \times 2$
$Total\,length = 20 + 4 = 24cm$
So, the correct answer is “Option B”.
Note:It should be noted that borders will exist on the both sides when the total length of the chess board is to be considered.Each statement given in the question needs to be understood carefully while converting them in mathematical form.
Recently Updated Pages
Questions & Answers - Ask your doubts

Master Class 9 Social Science: Engaging Questions & Answers for Success

Class 9 Question and Answer - Your Ultimate Solutions Guide

Master Class 8 Science: Engaging Questions & Answers for Success

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Master Class 9 English: Engaging Questions & Answers for Success

Trending doubts
The average rainfall in India is A 105cm B 90cm C 120cm class 10 biology CBSE

Why is there a time difference of about 5 hours between class 10 social science CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

Who Won 36 Oscar Awards? Record Holder Revealed

Indias first jute mill was established in 1854 in A class 10 social science CBSE

Indias first jute mill was established in 1854 in A class 10 social science CBSE

