A certain sum of money amounts to $Rs.6300/ - $ in $2$ years $Rs.7875/ - $ in $3$ years and $9$ months at simple interest. Find the rate of interest per annum.
Answer
643.2k+ views
Hint:In this question we are given that certain sum of money amounts to a particular amount in some given time at simple interest.Use the formula of simple interest for amount $Rs.6300/-$ and consider it as equation 1 .Then apply simple interest formula again for amount $Rs.7875/ - $ and consider it as equation 2.Now divide both equations to get the value of rate of interest per annum.
Formula used:$Amount = P\left( {1 + \dfrac{{T \times R}}{{100}}} \right)$ where $P$ is principal amount, $R\% $ is rate of interest, $T$ is the time period.
Complete step-by-step answer:
According to the question we need to find the rate of interest i.e. simple interest.
So, we will use the formula for simple interest,
$Amount = P\left( {1 + \dfrac{{T \times R}}{{100}}} \right)\,\,\,\,\,\,\,\, \to (1)$ where $P$ is principal amount, $R\% $ is rate of interest, $T$ is the time period. We are given that the sum of money amounts to $Rs.6300/ - $in $2$ years. So let $Rs.\,P$ be the principal amount and $R\% $ be the rate of interest per annum. Now using (1),
$6300 = P\left( {1 + \dfrac{{2 \times R}}{{100}}} \right)\,\,\,\,\,\,\,\,\,\,\, \to (2)$
Also we are given that a sum of money amounts to $Rs.7875/ - $in $3$ years and $9$ months.
Now the time period is not in years,
Time period $ = $ $3$years and $9$ months
$ = 3\dfrac{9}{{12}} = \dfrac{{15}}{4}$years
Now using (1) we get,
$7375 = P\left( {1 + \dfrac{{15 \times R}}{{400}}} \right)\,\,\,\,\,\,\,\,\,\, \to (3)$
Now dividing (2) by (3) we get,
$
\dfrac{{6300}}{{7375}} = \dfrac{{P\left( {1 + \dfrac{{2 \times R}}{{100}}} \right)\,}}{{P\left( {1 + \dfrac{{15 \times R}}{{400}}} \right)\,}} \\
\dfrac{4}{5} = \dfrac{{(100 + 2R)400}}{{(400 + 15R)100}} \\
\dfrac{4}{5} = \dfrac{{(100 + 2R)4}}{{(400 + 15R)}} \\
400 + 15R = 500 + 10R \\
15R - 10R = 500 - 100 \\
5R = 400 \\
R = 20\% \\
$
So we get the rate of interest per annum equal to $20\% $.
Note:In this question we take time period in years and generally we make this type of mistakes by not converting time period in years.
Formula used:$Amount = P\left( {1 + \dfrac{{T \times R}}{{100}}} \right)$ where $P$ is principal amount, $R\% $ is rate of interest, $T$ is the time period.
Complete step-by-step answer:
According to the question we need to find the rate of interest i.e. simple interest.
So, we will use the formula for simple interest,
$Amount = P\left( {1 + \dfrac{{T \times R}}{{100}}} \right)\,\,\,\,\,\,\,\, \to (1)$ where $P$ is principal amount, $R\% $ is rate of interest, $T$ is the time period. We are given that the sum of money amounts to $Rs.6300/ - $in $2$ years. So let $Rs.\,P$ be the principal amount and $R\% $ be the rate of interest per annum. Now using (1),
$6300 = P\left( {1 + \dfrac{{2 \times R}}{{100}}} \right)\,\,\,\,\,\,\,\,\,\,\, \to (2)$
Also we are given that a sum of money amounts to $Rs.7875/ - $in $3$ years and $9$ months.
Now the time period is not in years,
Time period $ = $ $3$years and $9$ months
$ = 3\dfrac{9}{{12}} = \dfrac{{15}}{4}$years
Now using (1) we get,
$7375 = P\left( {1 + \dfrac{{15 \times R}}{{400}}} \right)\,\,\,\,\,\,\,\,\,\, \to (3)$
Now dividing (2) by (3) we get,
$
\dfrac{{6300}}{{7375}} = \dfrac{{P\left( {1 + \dfrac{{2 \times R}}{{100}}} \right)\,}}{{P\left( {1 + \dfrac{{15 \times R}}{{400}}} \right)\,}} \\
\dfrac{4}{5} = \dfrac{{(100 + 2R)400}}{{(400 + 15R)100}} \\
\dfrac{4}{5} = \dfrac{{(100 + 2R)4}}{{(400 + 15R)}} \\
400 + 15R = 500 + 10R \\
15R - 10R = 500 - 100 \\
5R = 400 \\
R = 20\% \\
$
So we get the rate of interest per annum equal to $20\% $.
Note:In this question we take time period in years and generally we make this type of mistakes by not converting time period in years.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Class 10 Question and Answer - Your Ultimate Solutions Guide

Master Class 10 Maths: Engaging Questions & Answers for Success

Trending doubts
What is the Total Duration of Football Match?

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

In football, which nation is called "La Roja"?

Why is there a time difference of about 5 hours between class 10 social science CBSE

10 examples of evaporation in daily life with explanations

What is the full form of POSCO class 10 social science CBSE

