# A box is to be filled with mangoes, each weighing \[\dfrac{1}{{10}}kg\]. The weight of each box should not exceed $\dfrac{3}{5}kg$. Find the maximum number of mangoes that can be put inside the box.

(A) $6$

(B) $7$

(C) $8$

(D) $4$

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**Hint:**To find the maximum number of mangoes that can be put inside the box so that the weight of the box does not exceed $\dfrac{3}{5}kg$. So for that we derive an equation that contains weight of each mango and weight is less than and equal to $\dfrac{3}{5}kg$.

**Complete step-by-step answer:**

As we have to given that the Weight of each mango is = \[\dfrac{1}{{10}}kg\]

And Maximum weight capacity of each box is = $\dfrac{3}{5}kg$

Now Let assume that the maximum number of mangoes that can be put inside the box is equal to $x$

Now we have to find weight of $x$ mangoes, for that multiply weight of each mango to $x$

So weight of $x$ mangoes is = $\dfrac{1}{{10}} \times x$$kg$

Now as we know the total weight of box not exceed by $\dfrac{3}{5}kg$

So we can write it in linear inequality

$ \Rightarrow $ $\dfrac{1}{{10}} \times x \leqslant \dfrac{3}{5}$

Now rearrange this equation we get $x \leqslant \dfrac{3}{5} \times 10$

From this we get $x \leqslant 6$

Hence, the maximum number of mangoes that can be stored in a box is 6.

**So, the correct answer is “Option A”.**

**Note:**Shortcut method for this question or hit and trial method:

We have weight of each mango is $\dfrac{1}{{10}}kg$ and we have maximum weight that is $\dfrac{3}{5}kg$

So how many times we add each mango weight or from which number we multiply to each mango weight so that we reach up to the maximum limit of weight.

So we multiply it by $6$ so that $\dfrac{1}{{10}} \times 6$ = $\dfrac{3}{5}$

From this we can say our maximum number of mango is $6$.