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A bag contains 3,150 coins. There are 1 rupee coins, 2 rupee coins and 5 rupee coins in the bag. The ratio of each coin is 3:2:5 respectively. Then calculate the number of each coin.

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Hint: In order to solve this question first, find the sum of the ratio of 1, 2 and 3 rupee coins then divide the total number of coins in the ratio of 3:2:5 to get the number of 1, 2 and 3 rupee coins.

Complete step-by-step answer:
There are a total of 3150 coins in the bag.
The sum of the ratios of 1, 2 and 3 rupee coins is 3+2+5=10.
Then the numbers of 1 rupee coins will be $\dfrac{3}{{10}}$ part of 3150.
So, we do $\dfrac{3}{{10}}$x3150 = 945.
Therefore there are 945 coins of 1 rupee in the bag.

The numbers of 2 rupee coins will be $\dfrac{2}{{10}}$ part of 3150.
So, we do $\dfrac{2}{{10}}$x3150 = 630.
Therefore there are 630 coins of 2 rupee in the bag.

The numbers of 3 rupee coins will be $\dfrac{5}{{10}}$ part of 3150.
So, we do $\dfrac{5}{{10}}$x3150 =1575.
Therefore there are 1575 coins of 3 rupee in the bag.

Note: To solve these type of problems in which items divided in ratios are given and the total number of items are also given, to calculate the number of particular item we have to multiply the ratio upon the sum of ratios of all the item with the total number of items to get the number of that particular item. Similarly we can find the number of other items this way.