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Given,

Width of path running outside = 3 m

Length of rectangular park = 125 m

Breadth of rectangular park = 65 m

Area of rectangular park ABCD = length X breadth

$ = 125 \times 65 = 8,125{m^2}$.

Now, length of PQ = 125 + 3 + 3 = 131 m

Breadth of QR = 65 + 3 + 3 =71 m

$\text{Area of PQRS} = \text{length} \times \text{breadth}$

$ = 131 \times 71 = 9,301{m^2}$

Thus, the area of a path = Area of PQRS – Area of ABCD

$ = 9,301 - 8,125 = 1176{m^2}$.

Hence, the area of the path is $1176{m^2}$.