How is $1$ ohm related to ampere to volt?
Answer
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Hint: Resistance is defined as the amount of hindrance provided by the molecules of the conductor when current flows through it. Ampere and volt are units of electric current and potential difference respectively, whereas ohm is a unit of electric resistance.
Complete step by step answer:
Electric current is defined as the uniform flow of charges in a conductor when a potential difference is applied across the conductor. These charges can be positive charges, negative charges or even ions.Electric current flows through a conductor via the movement of electrons from a place of lower electric potential to a place of higher electric potential. Current flows in the opposite direction of the flow of electrons. So, current flows from higher potential to lower potential. While electrons flow through the conductor, its molecules provide hindrance to the moving electrons. That hindrance is known as Resistance$\left( R \right)$. When calculated,
$R \propto l$, and
$\Rightarrow R \propto \dfrac{1}{A}$, So
$\Rightarrow R \propto \dfrac{l}{A}$
$ \Rightarrow R = \rho \dfrac{l}{A}$
Where, $l = $ length of conductor, $A = $ Cross-section area of the conductor and $\rho = $ Resistivity of conductor.
According to Ohm’s Law, the potential difference $\left( V \right)$ across any two points in a conductor is directly proportional to electric current $\left( I \right)$ flowing through it. That is,
$V \propto I$
Eliminating the proportionality sign, the proportionality constant calculated is $K$.
$V = I.K$
Where, $K = \rho \dfrac{l}{A} = R$
$ \Rightarrow V = IR$
$ \Rightarrow R = \dfrac{V}{I}$
Let $V = 1V$ and $I = 1A$. So,
$R = \dfrac{{1V}}{{1A}}$
$\therefore 1\Omega = 1V/A$
Therefore $1\Omega $ is equal to $1V/A$.
Note:Resistivity of a conductor is a defining property of any conductor and is different for every conductor. Higher the resistivity, poorer the conductor. And lower the resistivity, better the conductor. Resistors are equipment used to provide resistance. They are attached to the circuit to regulate the flow of current through the conductor.
Complete step by step answer:
Electric current is defined as the uniform flow of charges in a conductor when a potential difference is applied across the conductor. These charges can be positive charges, negative charges or even ions.Electric current flows through a conductor via the movement of electrons from a place of lower electric potential to a place of higher electric potential. Current flows in the opposite direction of the flow of electrons. So, current flows from higher potential to lower potential. While electrons flow through the conductor, its molecules provide hindrance to the moving electrons. That hindrance is known as Resistance$\left( R \right)$. When calculated,
$R \propto l$, and
$\Rightarrow R \propto \dfrac{1}{A}$, So
$\Rightarrow R \propto \dfrac{l}{A}$
$ \Rightarrow R = \rho \dfrac{l}{A}$
Where, $l = $ length of conductor, $A = $ Cross-section area of the conductor and $\rho = $ Resistivity of conductor.
According to Ohm’s Law, the potential difference $\left( V \right)$ across any two points in a conductor is directly proportional to electric current $\left( I \right)$ flowing through it. That is,
$V \propto I$
Eliminating the proportionality sign, the proportionality constant calculated is $K$.
$V = I.K$
Where, $K = \rho \dfrac{l}{A} = R$
$ \Rightarrow V = IR$
$ \Rightarrow R = \dfrac{V}{I}$
Let $V = 1V$ and $I = 1A$. So,
$R = \dfrac{{1V}}{{1A}}$
$\therefore 1\Omega = 1V/A$
Therefore $1\Omega $ is equal to $1V/A$.
Note:Resistivity of a conductor is a defining property of any conductor and is different for every conductor. Higher the resistivity, poorer the conductor. And lower the resistivity, better the conductor. Resistors are equipment used to provide resistance. They are attached to the circuit to regulate the flow of current through the conductor.
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