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Last updated date: 08th Sep 2024

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As far as the NEET aspirants are concerned, one of the challenges they face while studying physics for the NEET exam is the mathematical operations and tools used at the time of solving numerical problems. However, this can be made easier if we learn the basic mathematical tools required in physics for the NEET exam.

In this article discussing the new and old mathematical tools in physics, we will see different physical constants and conversion coefficients that will come in handy while solving numerical problems. The importance of mathematics of tools like trigonometric functions of angles and their applications are discussed here. The application of differentiation and integration plays an important role in solving most of the physics problems in several chapters.

Now, let us move on to the important concepts and formulae of mathematical tools required in physics for the NEET exam, along with a few solved mathematical tools examples.

Quadratic equation

Binomial expansion

Important trigonometric identities.

Differentiation

Rules of differentiation

Applications of differentiation

Integration and its application

Definite integral

Integration Formulae

1. The position of a particle on x-axis that varies with time is given as x=3t^2+2t+1. Find the velocity of the particle at t=2 s.

Sol:

Given,

The position of the particle ,x=3t2+2t+1

The velocity of particle at t=2 s can be found by differentiating the displacement and substituting the value of t as 2 sec

$v=\dfrac{dx}{dt}$

$v=\dfrac{d}{dt}(3t^2+2t+1)$

$v=3\times2t+2$

$v=6t+2$

Put t=2 to calculate the velocity at that instant.

$v=6t+2$

$v=6\times2+2$

$v=14~m/s$

Therefore, the velocity of the particle at t=2 s is 14 m/s.Key point: Differentiating

displacement with respect to time gives velocity.

2. The variable force acting on a body of mass 1 kg depends on the displacement on x -axis as F=3x2+2. Find the work done by the variable force from x=0 to x= 2m.

Sol:

Given,

The variable force acting on the body, F=3x2+2

We can calculate the work done by the force by integrating force from x=0 m to x= 2m

$W=\int_{0}^{2} F.dx$

$W=\int_{0}^{2} (3x^2+2).dx$

$W=3\dfrac{[x^3]^2_0}{3}+2[x]^2_0$

$W=12~J$

Thus, the work done by the variable force from x=0 to x= 2m is 12J.

Key Point: The work done by a variable force can be obtained by integration of the variable force with respect to displacement.

1. A particle moves along a straight line OX. At a time t (in seconds), the distance x (in metres) is given by x=40+12t-t3. How long would the particle travel before coming to rest? (NEET 2006)

a. 24 m

b. 40 m

c. 56 m

d. 16 m

Sol:

The speed of the particle can be obtained by differentiating the distance with respect to time.

$v=\dfrac{dx}{dt}$

$v=\dfrac{d}{dt}(40+12t-t^3)$

$v=0+12-3\times t^2$

$v=-3t^2+12$

When particle comes to rest, the speed of the particle becomes zero

$0=-3t^2+12$

$t^2=4$

$t=2~s$

Now, the distance travelled by the particle is

$x=40+12t-t^3$

$x=40+12\times2-2^3$

$x=56~m$

Therefore, correct answer is option (c)

Trick: Speed of the particle can be obtained by differentiating the expression for distance with respect to time.

2. The displacement of a particle moving in a straight line is given by s=2t2+2t+4, where s is in metres and t is in seconds. The acceleration of the particle is (NEET 2001)

2 m/s2

4 m/s2

6 m/s2

8 m/s2

Sol:

The speed of the particle can be obtained by

$v=\dfrac{dx}{dt}$

$v=\dfrac{d}{dt}(2t^2+2t+4)$

$v=4t+2$

The acceleration of the particle is calculated as follows

$a=\dfrac{dv}{dt}$

$a=\dfrac{d}{dt}(4t+2)$

$v=4~m/s^2$

Therefore, correct answer is option (b)

Trick: When displacement of any object is given second-order differentiation will

be the acceleration of the object.

1. Find the work done to elongate a spring having a spring constant of 2000N/m from an extension of 1 cm to 2 cm.

Ans: 0.3 J

2. If v=x2-5x+4, find the acceleration of the particle when the velocity of the particle is zero.

Ans: 0 m/s2

In this article, we have provided important information under several mathematical tool names necessary for solving numerical problems in Physics. Students should have a better understanding of the mathematical operations so that students can score good marks in Physics for the NEET exam.

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NEET 2024 exam date and revised schedule have been announced by the NTA. NEET 2024 will now be conducted on 5 May 2024, and the exam registration starts on 9 February 2024 and closes on 9 March 2024. You can check the complete schedule on our site. Furthermore, you can check NEET 2024 dates for application, admit card, exam, answer key, result, counselling, etc along with other relevant information.

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NTA has announced the NEET 2024 application form release date on the official website https://neet.nta.nic.in/. The NEET 2024 Application Form is available on the official website for online registration from 9 February 2024 to 9 March 2024. Besides the NEET 2024 application form release date, learn about the application process, steps to fill out the form, how to submit it, the exam date sheet, etc online. Check our website for more details.

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NEET 2024 free online mock test series for exam preparation are available on the Vedantu website for free download. Practising these mock test papers of Physics, Chemistry and Biology prepared by expert teachers at Vedantu will help you to boost your confidence to face the NEET 2024 examination without any worries.
The NEET test series for Physics, Chemistry and Biology that is based on the latest syllabus of NEET and also the Previous Year Question Papers.

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NTA is responsible for the release of the NEET 2024 cut off score. The qualifying percentile score might remain the same for different categories. According to the latest trends, the expected cut-off mark for NEET 2024 is 50% for general category candidates, 45% for physically challenged candidates, and 40% for candidates from reserved categories. For the general category, NEET qualifying marks for 2024 ranged from 715-117 general category, while for OBC/SC/ST categories, they ranged from 116-93 for OBC, 116-93 for SC and 116-93 for ST category.

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The NEET 2024 result will be published by NTA on https://neet.nta.nic.in/ in the form of a scorecard on 14 June 2024. The scorecard will include the roll number, application number, candidate's personal details, and the percentile, marks, and rank of the candidate. Only those candidates who achieve the NEET cut-off will be considered qualified for the exam.

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NEET 2024 state rank lists will be released by the Medical Counselling Committee (MCC) for admissions to the 85% state quota and to all seats in private medical and dental colleges. NEET 2024 state rank lists are based on the marks obtained in medical entrance exams. Candidates can check the NEET 2024 state rank list on the official website or our site.

Want to know which Engineering colleges in India accept the NEET 2024 scores for admission to Engineering? Find the list of Engineering colleges accepting NEET scores in India, compiled by Vedantu. 1990 Colleges are accepting NEET Score. It includes 706 Medical, 323 Dental, 914 AYUSH, and 47 BVSc & AH colleges. Also find more details on Fees, Ranking, Admission, and Placement.

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FAQ

1. What are the main mathematical tools required in Physics for the NEET exam?

The main mathematical tools required for Physics in the NEET exam are differentiation and its applications, indefinite and definite integrations, trigonometric functions and their identities, measurement of positive and negative angles etc. You can download the mathematics tool pdf from Vedantu for easy reference.

**2. Is Calculus required for NEET?**

Some of the problems in Physics require a basic understanding of Calculus to solve problems in chapters like electrostatics, the system of particles, magnetic effects of current, etc. Even though students don't have to memorise all the Calculus formulas, they must know how to apply Calculus in a given situation to find the solution to the problems.

3. How to score good marks in Physics for the NEET exam?

First of all, understand all the concepts in depth and practise all the numerical problems in the NCERT textbook as well as other good study materials. Then, work out all the questions in the previous year's question papers. These will ensure that you will get good marks in physics for the NEET exam.

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