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Understanding the Tangent Secant Theorem in Circles

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Tangent Secant Theorem formula proof and solved examples

The tangent-Secant Theorem formula is a fundamental tool of Geometry found in Euclid’s Elements book. There are many methods to prove the theorem. Most important is using similar triangles. So, in this article, we will be discussing the proof of the Theorem in detail and its applications.


Terms associated with Circle


Terms Associated with Circle


History of Euclid


Euclid


Euclid


Name: Euclid

Born: Mid-4th century BC

Died: Mid-3rd century BC

Field: Mathematics

Nationality: Greek


Statement of Tangent-Secant Theorem


Circle with PT tangent and PQR secant


Circle with PT tangent and PQR secant


For a circle with centre O, consider PT to be the tangent to the circle at the point from external point P and PQR to be the secant to the circle with points Q and R on the circle, then Tangent-Secant Theorem is defined as:

$P Q \times P R=P T^{2}$


Proof of Secant Tangent Theorem


Proof of the Tangent Secant Theorem


Proof of the Tangent Secant Theorem


Given: PAB is secant to the circle with centre 0 and radius r. PT is tangent to the circle.

To prove: $P A \times P B=P T^{2}$

Construction: Draw $O D \perp A B$. Join $O P, O T$, and $O A$.

Proof:

Since $O D \perp A B$

$\therefore A D=D B \ldots(1)$ (Perpendicular from the centre to the chord bisects the chord)

$P A \times P B=(P D-A D)(P D \div B D)$

$\Rightarrow P A \times P B=(P D-A D)(P D+A D) \quad$ (Using 1)

$\Rightarrow P A \times P B=P D^{2}-A D^{2}$

In right $\triangle O P D$,

$O P^{2}=O D^{2}+P D^{2}$

$\Rightarrow P D^{2}=O P^{2}-O D^{2}$

$\therefore P A \times P B=\left(O P^{2}-O D^{2}\right)-A D^{2}$

$\Rightarrow P A \times P B=O P^{2}-\left(O D^{2}+A D^{2}\right)$

In right $\triangle O A D$,

$O A^{2}=O D^{2}+A D^{2}$

$\therefore P A \times P B=O P^{2}-O A^{2}$

$\Rightarrow P A \times P B=O P^{2}-O T^{2} \quad(\because O A=O T)$

In $\triangle O P T$,

$O P^{2}=P T^{2}+O T^{2}$

$\Rightarrow O P^{2}-O T^{2}=P T^{2}$

$\therefore P A \times P B=P T^{2}$

Hence proved.


Limitations of Tangent-Secant Theorem

  1. The tangent-Secant theorem doesn’t give any idea if the secant and tangent are not drawn from common points.

  2. Tangent-Secant Theorem is only applicable in the case of 2-dimensional circles and not in 3-dimensional figure spheres.


Applications of Tangent-Secant Theorem

  • Tangent-Secant Theorem is of great significance. It is used in our day-to-day life such as school buildings, bridges, monuments etc.

  • Monuments such as the Statue of Liberty and Pyramids are also based on concepts of secants and tangents.


Solved Examples

1. In the given figure, $P Q=12 \mathrm{~cm}, P T=24 \mathrm{~cm}$, then find $R Q$.


PQ and Tangent PT is given


PQ and Tangent PT is given


Ans:

Using Tangent Secant Theorem, we have

$P Q \times P R=P T^{2}$

Putting values, we get

$(12+x) \times 12=24^{2} \\$

$\Rightarrow(12+x) \times 12=576 \\$

$\Rightarrow(12+x)=48 \\$

$\Rightarrow x=48-12 \\$

$\Rightarrow x=36$

So, we get

$R Q=36 \mathrm{~cm}$


2. In a circle, the tangent is drawn from outside point $P$ to the circle at point $T$ and from the same point secant is drawn to the circle intersecting the circle at $Q$ and $R$, respectively, such that $P Q=25 \mathrm{~cm}, R Q=9 \mathrm{~cm}$, then find $P T$.

Ans:

According to the question, we get the following figure:


Secant PQR is given


Secant PQR is given


Using Tangent Secant Theorem, we have

$P Q \times P R=P T^{2}$

Putting values, we get

$(25+9) \times 25=P T^{2} \\$

$\Rightarrow P T^{2}=34 \times 25$

$\Rightarrow P T^{2}=850 \\$

$\Rightarrow P T=\sqrt{850} \\$

$\Rightarrow P T=29.154$

So, we get

$P T=12.154 \mathrm{~cm}$


3. In the given figure, $P R=84 \mathrm{~cm}, P T=42 \mathrm{~cm}$, then find $R

Q$.


Secant and tangent from a point are given


Secant and tangent from a point are given


Ans:

Using Tangent Secant Theorem, we have

$P Q \times P R=P T^{2}$

Putting values, we get

$P Q \times 84=42^{2} \\$

$\Rightarrow P Q \times 84=1764 \\$

$\Rightarrow P Q=21$

Now,

$R Q=P R-P Q$

And,

$P Q=21 \\$

$\Rightarrow R Q=84-21 \\$

$\Rightarrow R Q=63 \mathrm{~cm}$


Important Formulas to remember

  • $P Q \times P R=P T^{2}$, where $\mathrm{PT}$ is tangent and $\mathrm{PQR}$ is secant to the circle with centre $O$ and radius $r$.


Important Points to Remember

  • A Tangent line touches the circle at only one point.

  • A Secant line touches the circle at exactly two points.


Conclusion


In the article, we have discussed the proof of the Tangent-Secant Theorem and its applications in detail. The Tangent Secant Theorem helps us in solving mathematical problems. In the world of art, architecture, and the growing demands of infrastructure, the tangent secant theorem places itself at the centre of its applications. In all, we can say that the theorem is of great importance.

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FAQs on Understanding the Tangent Secant Theorem in Circles

1. What is the Tangent Secant Theorem?

The Tangent Secant Theorem states that when a tangent and a secant are drawn from the same external point to a circle, the square of the tangent segment equals the product of the secant’s external part and its entire length. In formula form: (tangent length)² = (external secant part) × (whole secant length). This theorem is used in circle geometry to find unknown lengths involving tangents and secants.

2. What is the formula for the Tangent Secant Theorem?

The formula for the Tangent Secant Theorem is t² = a(a + b), where t is the tangent length, a is the external part of the secant, and b is the internal part of the secant.

  • t = tangent segment
  • a = external segment of secant
  • a + b = entire secant length
This formula helps calculate missing segment lengths in circle problems.

3. How do you use the Tangent Secant Theorem to solve a problem?

To use the Tangent Secant Theorem, substitute known values into the formula t² = a(a + b) and solve for the unknown.

  • Step 1: Identify the tangent length and secant parts.
  • Step 2: Write the equation using t² = a(a + b).
  • Step 3: Substitute known values.
  • Step 4: Solve the resulting equation.
This method is commonly used in geometry exams and circle theorems questions.

4. Can you give an example of the Tangent Secant Theorem?

Yes, for example, if the external secant part is 3 units and the internal part is 5 units, then the tangent length is found using t² = 3(3 + 5).

  • t² = 3 × 8
  • t² = 24
  • t = √24
  • t ≈ 4.9 units
This shows how the tangent length is calculated using the theorem.

5. Why does the Tangent Secant Theorem work?

The Tangent Secant Theorem works because of triangle similarity formed by angles inside the circle configuration. When a tangent and secant are drawn from the same external point, similar triangles are created, leading to proportional relationships. These proportional sides simplify to the formula t² = a(a + b).

6. What is the difference between the Tangent Secant Theorem and the Secant Secant Theorem?

The difference is that the Tangent Secant Theorem involves one tangent and one secant, while the Secant Secant Theorem involves two secants drawn from the same external point.

  • Tangent Secant: t² = a(a + b)
  • Secant Secant: a(a + b) = c(c + d)
Both are circle theorems used to find unknown segment lengths.

7. What conditions are required to apply the Tangent Secant Theorem?

The Tangent Secant Theorem applies only when a tangent and a secant are drawn from the same external point outside a circle.

  • One line must touch the circle at exactly one point (tangent).
  • The other line must intersect the circle at two points (secant).
  • Both must share the same external starting point.
Without these conditions, the theorem cannot be used.

8. How is the Tangent Secant Theorem related to circle geometry?

The Tangent Secant Theorem is a key result in circle geometry that relates external line segments drawn to a circle. It connects tangents, secants, and segment lengths through the equation t² = a(a + b). This relationship is part of a broader set of power of a point theorems used in geometric proofs and calculations.

9. What is the Power of a Point in relation to the Tangent Secant Theorem?

The Power of a Point states that for a point outside a circle, the product of secant segments or the square of a tangent segment is constant. The Tangent Secant case is expressed as t² = a(a + b). This means the tangent length squared equals the power of that external point with respect to the circle.

10. What are common mistakes when using the Tangent Secant Theorem?

Common mistakes include misidentifying segment lengths and using the wrong formula.

  • Forgetting to square the tangent (t²).
  • Using only the internal secant part instead of the whole secant.
  • Applying the theorem when lines do not share the same external point.
Always remember the correct formula: t² = a(a + b).