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Solutions for CBSE Class 11 Maths Chapter 11 - Trigonometric Equations (By RD Sharma)

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Solutions for Class 11 Maths Chapter 11 by RD Sharma- Free PDF Download

Solutions for Class 11 Mathematics Chapter 11 “Trigonometric Equations” by RD Sharma are available here at Vedantu solved by expert teachers as per the latest CBSE Board syllabus and NCERT Book guidelines. ‘Trigonometric Equations’ is the eleventh chapter in the CBSE Mathematics textbooks for Class 11 students. ‘Trigonometric Equations’ chapter is explained majorly related to Class 11 consists of trigonometric equations concepts. These equations contain unknown angles which are found in trigonometric forms. These values cover the Trigonometric Equations Class 11 syllabus. Students are suggested to use RD Sharma Class 11 Chapter 11 Solutions as the best reference material that helps them to score more marks in their exams. 

Question: How can we download solutions for Class 11 Mathematics Chapter 11 “Trigonometric Equations” by RD Sharma?

Answer: Students can download the solutions Class 11 Mathematics Chapter 11 “Trigonometric Equations”  by RD Sharma from Vedantu.com. 

RD Sharma Class 11 Chapter 11 Solutions are the best material for weak students who feel difficulty in solving trigonometric equations. The chapter-wise examples in RD Sharma make a student boost his confidence before exams. The exercises have a collection of different problems that improve the knowledge of the student. With the help of this, you also get an idea of time management regarding answering the questions in a particular period.

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Class 11 RD Sharma Textbook Solutions Chapter 11 - Trigonometric Equations

What are Trigonometric Equations?

The Trigonometric Equations Class 11 are ones which have trigonometric quantities and ratios of not known angles. The trigonometric ratios can be from the six ratios we have: secant, cosec, cosine, sine, cotangent and tangent. For example, 2 sinx + cos2(2x) + 1 = 0 and sinx = 0. From the above trigonometry equation Class 11, it is obvious that x is the variable, and it is the unknown angle. Hence, suppose for the equation sinx=0, we need to calculate all the values of x for which the expression sinx is equal to zero. Also have a look at Exercise 11.1 to cover all the questions.

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What is The Method to Solve Trigonometry Equations?

Students must pay more attention while solving Trigonometric Equations for Class 11. Each question has a different approach to complete. Let's discuss some basic question patterns and types.

First Type: Some equations can be written in terms of quadratic format, factor multiplication or equations that can get factorized. Here, in the first type, we will discuss such equations. The first step is to convert the equation to factors and then solve each element individually. The final result will be the result of the union of all the solutions that came from each aspect. 

Second Type: For final exams, these types of equations are very important. Such equations can be found in RD Sharma Class 11 Chapter 11 solutions. These equations can be written in the form of x cosA + y sinB = z. The first step is to convert the given equation to the general form of x cosA + y sinB = z. Then secondly you need to assume, x = a cos(theta) and y = a sin(theta). Again let us say, a = √(x2 + y2) and tan(theta) = y/x. After the substitution step we get {a cos(theta)cosA + a sin(theta)sinB = z}. Now one can deduce the answer with cos(A-B) and get the final solutions.

Third Type: Here, we need to study the equations which require transformation from trigonometric function sum form to product form. In such equations, each angle is different with a different value. What one needs to do is put the equation in the sinA + sinB record. Hence from here, you can get each angle familiar on both sides.

Fourth Type: The fourth type of question is also given in RD Sharma Class 11 trigonometric equation solution. It is the reverse process of the previous type. Here the product form of trigonometric functions is transformed to a sum state. The trigonometric ratios of products need to transform into the sum term. Then you can simplify it.

Fifth Type: There are some equations where you need the substitution process or variable change to solve it. You can find ample of such problems in RD Sharma Class 11 trigonometric equation solution series. If an equation involves f( sinA +- cosA, sinAcosA ) = 0 where f(x, y) is one polynomial term, then here we have a special type of substitution process. Here it would help if you substituted sinA +- cosA = z. Then we can again rewrite the same as 1 +- 2 sinAcosA = z2. Therefore, sinAcosA = +- (z2 -1)/2.

RD Sharma Class 11 Chapter 11 Solutions

This chapter provides an overview of trigonometric equations (the equations containing trigonometric functions of unknown angles are known as trigonometric equations). For students who have trouble understanding the concepts of this chapter, Vedantu's experts have designed content based on students' ability to understand them. Students can solve chapter-wise problems by increasing their level of confidence before attending a board exam. Trigonometric Equations comprise one exercise and the RD Sharma Solutions provided on this PDF provide solutions to the questions which are present in the exercise. 

Now, Let's Look at the Topics Mentioned in this Chapter:

  • Definitions.

  • General solutions of trigonometric equations.

  • General solutions of trigonometric equations in specific forms.

Tips on How to Prepare for Exams Using Trigonometric Equations Class 12 RD Sharma

Vedantu gives top-notch content on Trigonometric Equations as per the exam pattern of CBSE by thoroughly checking the weightage of the marks. 

Students can follow the mentioned tips while going through this PDF of RD Sharma Class 11 Chapter 11 Solutions.

  • First, brush up on the basics from previous classes of trigonometric functions.

  • Read the question carefully before answering. When solving RD Sharma questions, we advise students to not look at the solutions directly. Instead, first, solve the solutions on your own and later compare them with RD Sharma Trigonometric Equations Class 11 Solutions. By doing this students will get a proper idea of how to solve a particular problem in Trigonometric Equations. 

  • Since Vedantu provides a step-by-step approach to solutions, students can easily prepare without missing any steps. This helps students to grasp all intermediate steps used while solving the problems.

  • If students want to gain more subject knowledge on the topic and to excel in the examination, they can solve the extra practice and exercise problems that are provided in this free PDF of RD Sharma Trigonometric Equations Class 11 Solutions.

Solved Examples

Q1. What Are the Essential Trigonometric Functions?

Answer: The fundamental trigonometric functions include cosine, sine and tangent functions.

Q2. Write Down the Three Identities of Trigonometry.

Answer: The fundamental trigonometric identities are: sin²a + cos²a = 1, tan²a + 1 = sec²a and cot²a + 1 = cosec²a.

Conclusion

Students will be confident while studying through this PDF of RD Sharma Trigonometric Equations Class 11 Solutions. The solutions to every problem are designed carefully in a step-by-step manner so that students feel that they have covered all their basics on Trigonometric Equations before sitting for their exams. Students can download free PDFs available on the Vedantu platform.

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FAQs on Solutions for CBSE Class 11 Maths Chapter 11 - Trigonometric Equations (By RD Sharma)

1. What is the general method for solving trigonometric equations as per the RD Sharma Class 11 solutions?

The general method provided in RD Sharma solutions for Class 11 Maths Chapter 11 involves a systematic approach. First, simplify the given trigonometric equation using identities to express it in terms of a single trigonometric function. Next, reduce it to one of the basic forms, such as sin x = sin α, cos x = cos α, or tan x = tan α. Finally, apply the corresponding general solution formula to find all possible values for the variable, ensuring compliance with the CBSE 2025-26 syllabus.

2. How do RD Sharma solutions handle trigonometric equations involving squared terms like sin²x or tan²x?

RD Sharma solutions demonstrate how to solve equations with squared terms by converting them into simpler forms. The key steps are:

  • Use trigonometric identities like sin²x = (1 - cos2x)/2, cos²x = (1 + cos2x)/2, or sec²x = 1 + tan²x.
  • These identities help reduce the degree of the equation, transforming it into a linear equation with a multiple angle (e.g., an equation in terms of cos2x).
  • Once transformed, the equation can be solved using the standard methods for general solutions.
This approach simplifies complex problems into manageable steps.

3. Are the RD Sharma solutions for Chapter 11 sufficient for mastering both Principal and General Solutions for Class 11 exams?

Yes, the solutions for RD Sharma Chapter 11 provide comprehensive coverage for both types of solutions. The exercises clearly distinguish between finding:

  • Principal Solutions: These are the solutions that lie within a specific interval, typically [0, 2π). The solutions guide you on how to identify these specific values.
  • General Solutions: These represent all possible solutions and are expressed using an integer 'n' (e.g., x = 2nπ ± α for cosine). The book offers extensive practice problems to master the application of these general formulas, which is crucial for exams.

4. What is the most common mistake students make when finding the general solution for equations like cos x = cos y?

A very common mistake is confusing the general solution formulas for different trigonometric functions. For an equation of the form cos x = cos y, the correct general solution is x = 2nπ ± y. Students often incorrectly use the formula for sine, which is x = nπ + (-1)ⁿy. The RD Sharma solutions help prevent this by providing numerous solved examples where the correct formula is explicitly stated and applied, reinforcing the proper method for each function.

5. How do the methods for solving trigonometric equations in RD Sharma differ when dealing with trigonometric inequalities?

While related, the methods differ significantly. Solving a trigonometric equation gives you specific points, whereas solving an inequality gives you a range or interval of values. The process shown in RD Sharma typically involves:

  • First, treating the inequality as an equation to find the critical points where the expression equals zero or is undefined.
  • Next, using these points to divide the number line (or the interval [0, 2π]) into different regions.
  • Finally, testing a value from each region in the original inequality to determine which intervals satisfy the condition.

6. Why is checking for extraneous solutions important when solving trigonometric equations, and how do RD Sharma solutions guide this?

Checking for extraneous solutions is crucial because certain mathematical operations, like squaring both sides of an equation, can introduce solutions that do not satisfy the original equation. For example, when solving an equation with square roots like √(1 – cos x) = sin x, you must ensure that sin x ≥ 0. RD Sharma solutions often highlight the verification step, where the obtained solutions are substituted back into the original equation to confirm their validity and discard any extraneous roots.

7. What special cases of trigonometric equations are covered in the RD Sharma Class 11 solutions for Chapter 11?

Beyond standard problems, RD Sharma solutions for Chapter 11 cover special cases that require logical reasoning rather than just formulas. A key type is solving equations using the concept of boundedness. For instance, an equation like sin x + cos y = 2 can only be solved by recognizing that the maximum value of sin x and cos y is 1. Therefore, the only possible solution is when sin x = 1 and cos y = 1 simultaneously. This requires an understanding of the range of trigonometric functions.

8. How do the initial exercises in RD Sharma Chapter 11 build a foundation for solving complex trigonometric equations?

The initial exercises, such as Exercise 11.1, are designed to build a strong foundation by focusing on the basics. They primarily deal with finding the principal solutions of simple equations like sin θ = 1/2 or tan θ = -1. By mastering the process of identifying values within the 0 to 2π range, students develop the essential skill of relating angles to trigonometric ratios. This fundamental understanding is necessary before moving on to the more abstract concept of general solutions for complex equations in later exercises.