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# RD Sharma Class 11 Maths Solutions Chapter 16 - Permutations Last updated date: 28th Nov 2023
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## RD Sharma Solutions for Class 11 Maths Chapter 16 - Free PDF Download

Permutations and combinations are the different ways in which objects from a set may be selected to form subsets, usually without a substitution. When the order of selection is a factor, this selection of subsets is called a permutation, we use combination when order is not a factor. Permutation and Combination class 11 RD Sharma is one of the most important chapters in board exams as well as in competitive exams. The RD Sharma Class 11 Chapter 16 Solutions are prepared according to the NCERT curriculum by experts.

All solutions are explained clearly in a step-by-step manner to provide a unique learning experience to students. The RD Sharma Solutions of Class 11 Maths Chapter 16 also have a lot of exercise and practice problems so that students will have enough practice of the subject before their exams. Students can download a free PDF of Permutation and Combination class 11 RD Sharma solutions free of cost.

## Chapter 16 - Permutations

Students can use these permutations to help them get good grades on their board exams. From a set of 'n' objects, the number of possible 'r' object pairings. As a result, permutations are employed for lists (where the order is important) and combinations for groups (where the order is irrelevant). This chapter will introduce the terms factorial and factorial notation. The RD Sharma Solutions module uses a variety of shortcut hints and pictures to explain all of the exercise issues in plain English.

There are five exercises in Permutations, and the RD Sharma Solutions provide precise answers to the questions in each one. Vedantu's specialists have broken down tough problems into easy steps that students can solve quickly and accurately. RD Sharma Class 11 Maths Solutions can assist students in gaining a thorough understanding of the topic. As a result, students should practice the solutions by obtaining the pdf from the links provided below. Let's take a closer look at the principles covered in this chapter.

• The factorial.

• Fundamental principles of counting.

• Permutations.

• Permutations under certain conditions.

• Permutations of objects are not all distinct.

### What is Permutation?

A permutation is an arrangement of a number of objects in a specific order, taken one at a time or all at once. Consider the following ten numbers: 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9. P(10,4) = 5040 is the number of different 4-digit-PINs that may be constructed using these 10 digits. This is a simple permutation example. Permutations of four numbers drawn from a set of ten numbers equal to the factorial of ten divided by the factorial of the difference between ten and four. The permutations are simple to calculate.

## FAQs on RD Sharma Class 11 Maths Solutions Chapter 16 - Permutations

1. What are permutations with repetition of class 11 chapter 16?

Permutations with repetition are used by statisticians when the outcomes of a permutation can be repeated. In a four-digit PIN, for example, you can repeat values like 1-1-1-1. This is also known as permutations with replacement by analysts.

To find the number of permutations, multiply the number of possibilities for each event by itself X times, where X equals the number of events in the sequence. Each digit in a four-character PIN, for example, can range from 0 to 9, giving us a total of ten possibilities for each digit. There are four digits in all.  As a result, with these PINs, the number of permutations with repetition is 10 * 10 * 10 * 10 = 10,000.

2. How to use chapter 16 of class 11 RD Sharma, permutations to calculate probabilities?

Permutations are sequences of outcomes where the order matters in probability theory and other disciplines of mathematics. Because the order of the numbers is important, 9-6-8-4 is a permutation of a four-digit PIN. Computing the number of possible permutations to determine the likelihood of an event is frequently required when calculating probabilities.

If you're given a permutation-based probability problem to solve, you'll need to follow these steps.

• Calculate the probability using a ratio.

• Calculate whether the numerator and denominator require combinations, permutations, or a mixture of the three. Here, we'll focus on permutations.

• Is this a permutation with repetitions, a permutation without repetitions, or a mix of both?

• For both types of repetition, you must determine the n and r to use in the equations.

3. Where can I find RD Sharma’s class 11 chapter 16 solutions?

4. How can I achieve good marks in chapter 16 of class 11 permutation?

• Students can obtain valuable practice for the final exam by tackling sample papers. Also, try to solve question papers from prior years. It will assist in gaining an understanding of the question structure and marking scheme.

• Before beginning to tackle the permutation question, the student should go through the entire question paper and see which questions they can easily answer. Solve the problems you know the answer to so you can go on to the next question. Also, look over the questions that have a lot of weight and be sure to answer them all.

• Half the battle is won if you study regularly and finish your CBSE Class 11 permutation Syllabus on time. Finish your projects, assignments, and practicals on the due date to get them out of the way. Begin with the easier questions and work your way up to the more challenging ones. Even the most challenging queries will meltdown to simpler, easier concepts once you've brushed up on the fundamentals.

5. Is chapter 16 of RD Sharma class 11-Permutation used in real life? How?

Yes, permutation is used in real life. For example-

A permutation is seating four people in five chairs.

Let's say you're throwing a party for your sibling’s birthday, and you've invited 10 close friends because you know there are only 10 chairs in your house. The real issue arises when you learn that your wife has given one chair to your neighbour because some guests have visited their home and they're short of one chair, and your wife's nature is very kind and helpful. So, now that you know this, you're worried about what you'll do next. So, after much thought, you've decided to arrange 10 people in 9 seats using the concept of permutation, and you can arrange 10 people in 9 chairs in 10P9 = 10 factorial or 362880 ways.

So there are 362880 different ways to assemble 10 people on 9 chairs.

So this is only a simple real-life application of permutation, and there are many others, such as seating four employees of a company in six distinct chairs or placing six different fruits in five trays.