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RD Sharma Class 10 Solutions Chapter 9 - Exercise 9.3

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RD Sharma Class 10 Solutions Chapter 9 - Arithmetic Progressions (Ex 9.3) Exercise 9.3 - Free PDF

Free PDF download of RD Sharma Class 10 Solutions Chapter 9 - Arithmetic Progressions Exercise 9.3 solved by Expert Mathematics Teachers on Vedantu.com. All Chapter 9 - Arithmetic Progressions Ex-9.3 Questions with Solutions for RD Sharma are available to help you to revise complete Syllabus and score more marks. Register for online coaching for IIT JEE (Mains & Advanced) and other Engineering entrance exams. Register Online for Class 10 Science tuition on Vedantu.com to score more marks in CBSE board examination.


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General Vocabulary used in Arithmetic Progressions

While studying the arithmetic progression, we may come across the following terms. 


First Term: As given by its name, the first term in an AP is the first term in the progression. It is usually represented by a1 or simply a. For example, in sequence 2,4,6,8,10…. 2 is the first term. 


Common Difference: As mentioned above, an AP is a sequence where every term, except the first term, is obtained by adding a fixed number to its previous term. This fixed number is called the “common difference” and it is generally denoted by 'd'. If the first term is a1, then: the second term is a1+d, the third term is a1+d+d = a1+2d, and the fourth term is a1+2d+d= a1+3d and the sequence goes on. For example, in the sequence 2,4,6,8,10. . . Each term, except the first term which is 2, is obtained by adding 2 to its previous term. So, in this case, the common difference is, d=2. Generally, the common difference is the difference between every two successive terms of an Arithmetic progression. Hence, the formula to calculate the common difference of an AP is:  d=an-a{n-1}


The General Term of an Arithmetic Progression (nth Term)

The general term also called the nth term of an AP, whose first term is a and the common difference is d, is found by the formula an=a+(n-1)d. 

 

The Formula for Calculating Sum of Arithmetic Progression

Consider an arithmetic progression sequence whose first term is a1 or a and the common difference is d.

  • The sum of the first n terms of an arithmetic progression when the nth term is not known to us is Sn = n/2[2a+(n-1) d] 

 

  • The sum of the first n terms of an arithmetic progression when the nth term, an is known to us is Sn = n/2[a1+an


Derivation of the Arithmetic Progression Formula

To find the nth term of an arithmetic progression, we know that the nth term, an=a1+(n–1)d, where, a1 is the first term, a1 + d is the second term, the third term is a1 + 2d, and the sequence goes on. For finding the sum of the arithmetic series, say Sn, we start with the first term and successively add the common difference to the next coming terms.

 

Sn = a1 + (a1 + d) + (a1 + 2d) + … + [a1 + (n–1)d].

 

Also, we can start with the nth term and successively subtract the common difference.

 

Sn = an + (an – d) + (an – 2d) + … + [an – (n–1)d].

 

So, the sum of the arithmetic sequence could be found in any of the two ways. However, 

on adding those two equations together, we will be getting

 

Sn = a1 + (a1 + d) + (a1 + 2d) + … + [a1 + (n–1)d]

Sn = an + (an – d) + (an – 2d) + … + [an – (n–1)d]

_________________________________________

2Sn = (a1 + an) + (a1 + an) + (a1 + an) + … + [a1 + an]

____________________________________________

 

We can notice that all the terms that have d are added out. Hence,

2Sn = n (a1 + an)

Sn = [n(a1 + an)]/2

 

By substituting an = a1 + (n – 1)d into the last formula, we have

Sn = n/2 [a1 + a1 + (n – 1)d] ...Simplifying

Sn = n/2 [2a1 + (n – 1)d].

 

These two formulas help us to find the sum of an arithmetic sequence quickly.

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FAQs on RD Sharma Class 10 Solutions Chapter 9 - Exercise 9.3

1. What are the key formulas from Chapter 9 required to solve the problems in RD Sharma Class 10 Exercise 9.3?

To solve the problems in Exercise 9.3, which primarily deals with the sum of terms in an Arithmetic Progression, you will mainly use the following two formulas:

  • The formula for the sum of the first 'n' terms: S_n = n/2[2a + (n-1)d], where 'a' is the first term, 'd' is the common difference, and 'n' is the number of terms.

  • An alternative formula for the sum when the last term ('l') is known: S_n = n/2(a + l).

You may also need the formula for the nth term, a_n = a + (n-1)d, to find the number of terms 'n' or the last term 'l' before you can calculate the sum.

2. What is the correct step-by-step method to find the sum of an AP as per the solutions for Exercise 9.3?

The correct step-by-step method to find the sum of an Arithmetic Progression (AP) is as follows:

  • Step 1: Identify the known values from the problem, which are typically the first term (a), the common difference (d), and the number of terms (n).

  • Step 2: Choose the appropriate sum formula. If the last term (l) is known, use S_n = n/2(a + l). Otherwise, use S_n = n/2[2a + (n-1)d].

  • Step 3: Substitute the identified values of a, d, and n into the chosen formula.

  • Step 4: Perform the calculations carefully, paying close attention to the order of operations and signs, to find the final sum (S_n).

3. How do I decide whether to use the formula S_n = n/2(a + l) or S_n = n/2(2a + (n-1)d) for a given problem?

Your choice of formula depends on the information provided in the question. You should use:

  • S_n = n/2(a + l) when you know the first term (a), the last term (l), and the total number of terms (n). This is the more direct and quicker method in such cases.

  • S_n = n/2[2a + (n-1)d] when you know the first term (a), the common difference (d), and the number of terms (n), but the last term is not given.

4. How are the nth term (a_n) and the sum of n terms (S_n) of an AP related? Can I find a specific term using only the sum formulas?

Yes, the nth term and the sum of n terms are closely related. The nth term of an AP is the difference between the sum of the first 'n' terms and the sum of the first 'n-1' terms. This gives a very useful relationship: a_n = S_n - S_{n-1}. This means if you know the general formula for the sum of 'n' terms of an AP, you can find any specific term without knowing the first term or common difference directly.

5. What are the common mistakes to avoid when solving problems from Exercise 9.3 involving the sum of an AP?

When solving for the sum of an AP, students often make a few common errors. Be careful to avoid:

  • Calculation Errors: Simple mistakes in arithmetic, especially with negative signs for the common difference (d).

  • Formula Errors: Forgetting to multiply by 'n/2' or using 'n' instead of '(n-1)' inside the bracket of the formula S_n = n/2[2a + (n-1)d].

  • Incorrect 'n': Miscalculating the number of terms 'n' before applying the sum formula. Always double-check how you found 'n'.

  • Quadratic Equation Mistakes: When finding 'n' from a given sum, you may get a quadratic equation. Ensure you solve it correctly and choose the valid positive integer value for 'n'.

6. How do I solve a problem where the sum (S_n) is given, and I need to find the number of terms (n)?

To find the number of terms (n) when the sum (S_n) is given, you should follow these steps:

  • 1. Write down the formula S_n = n/2[2a + (n-1)d].

  • 2. Substitute the known values of S_n, the first term (a), and the common difference (d) into the equation.

  • 3. Simplify the equation. This will typically result in a quadratic equation of the form An² + Bn + C = 0.

  • 4. Solve this quadratic equation for 'n' using methods like factorization or the quadratic formula.

  • 5. Since 'n' represents the number of terms, it must be a positive integer. Discard any negative or fractional solutions.

7. In some problems, the sum of an AP can be zero or negative. What does this practically mean?

A zero or negative sum in an AP has a practical meaning. A zero sum (S_n = 0) implies that the sum of all the positive terms in the progression is perfectly cancelled out by the sum of all the negative terms. A negative sum (S_n < 0) indicates that the cumulative value of the negative terms in the sequence is greater than the cumulative value of the positive terms. This often happens in progressions that start with positive terms but have a negative common difference.