
Write the formula to find the magnitude of the gravitational force between the earth and an object on the surface of the earth.
Answer
552k+ views
Hint: To solve this question we have to know briefly about gravitational force. Newton's Law of Universal Gravitation is utilized to clarify gravitational power. This law expresses that each monstrous molecule in the universe pulls in each other gigantic molecule with a power which is straightforwardly corresponding to the result of their masses and contrarily relative to the square of the distance between them. This general, actual law was gotten from perceptions made by enlistment.
Complete step by step answer:
Another way, more current, approach to express the law is: 'each point mass draws in each and every other point mass by a power pointing along the line crossing the two focuses. The power is corresponding to the result of the two masses and conversely relative to the square of the distance between the point masses'.
We know that, The gravitational force between the earth and an object on the surface of the earth is \[F = G\dfrac{{Mm}}{{{d^2}}}\]
Where we know that, $G$ is the universal gravitational constant. And here $M$ is the mass of earth. $m$ is known to the mass of an object on the surface of earth and we can assume now that $d$ is the distance between two bodies.
Note: We have to know that, The gravitational field is the negative differential of the gravitational potential. Presently the gravitational potential because of a molecule a ways off $r$ is $ −G\dfrac{m}{r}$ where $m$ is the mass of the molecule.
Complete step by step answer:
Another way, more current, approach to express the law is: 'each point mass draws in each and every other point mass by a power pointing along the line crossing the two focuses. The power is corresponding to the result of the two masses and conversely relative to the square of the distance between the point masses'.
We know that, The gravitational force between the earth and an object on the surface of the earth is \[F = G\dfrac{{Mm}}{{{d^2}}}\]
Where we know that, $G$ is the universal gravitational constant. And here $M$ is the mass of earth. $m$ is known to the mass of an object on the surface of earth and we can assume now that $d$ is the distance between two bodies.
Note: We have to know that, The gravitational field is the negative differential of the gravitational potential. Presently the gravitational potential because of a molecule a ways off $r$ is $ −G\dfrac{m}{r}$ where $m$ is the mass of the molecule.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

What organs are located on the left side of your body class 11 biology CBSE

Draw a labelled diagram of the human heart and label class 11 biology CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

