Question

Write the chemical names of the following compound:
$$(C{H}_{3}COO{)}_{2}Pb$$

Answer 1

Hint:We know that in organic chemistry, the chemical formula provides us a way to represent any chemical substance using the symbol of the elements present in it. The molecular formula for the compound acetate is $$C{H}^{3}CO{O}^{-}$$ and ‘Pb’ is lead.

Complete answer:
$$C{H}^{3}CO{O}^{-}$$ is the acetate ion which means it has a negative charge of $$-1$$. This ion is very common, for instance vinegar is, for the most part, acetic acid CH3COOH. This means that the negative charge of -1 has been filled with a hydrogen proton, charge of $$+1$$.
And Pb stands for the element ‘Lead’. Since. there are two oxidation state of Pb i.e. $$+2$$ and $$+4$$ then the only way for the total charge of the compound to be zero is:
$$\Rightarrow Pb\left(+2\right)+2acetate\left(-1\right)=2+\left(-2\right)=0$$
Hence, the oxidation state of the lead is $$+2$$ here.
So, the name of the compound $$(C{H}_{3}COO{)}_{2}Pb$$ is known as lead (II) acetate or commonly known as lead acetate and it is a type of sweet, white powder that is crystal-like. It is also soluble in both water and glycerine.

Therefore, the chemical name of the compound $$(C{H}_{3}COO{)}_{2}Pb$$ is Lead(II) acetate.

Note:
It should be noted that the other name of Lead(II) acetate ($$Pb{\left(C{H}_{3}COO\right)}_2$$), are also lead acetate, lead diacetate, plumbous acetate, sugar of lead, lead sugar, salt of Saturn, lead salt, or Goulard's powder. Lead(II) acetate is used as a reagent to make other lead compounds and also as a fixative for some dyes. In low concentrations, it is the principal active ingredient in progressive types of hair colouring dyes.