Answer
Verified
384k+ views
Hint: In order to balance the chemical equations, the number of atoms of each specific element on the reactant side should be equal to the number of elements of that element on the product side too.
Complete step by step answer:
In order to answer our question, we need to learn about the laws of chemical combination. Now, we know that in any chemical reaction, energy can neither be created nor destroyed. The same applies to mass. Mass remains constant, i.e total mass of the reactants is equal to the mass of the products. Also, no new element can suddenly come out in the reaction. For example in the reaction of ${{H}_{2}}$ and ${{O}_{2}}$ to form ${{H}_{2}}O$, the only elements present are hydrogen and water. No new element like nitrogen has entered the reaction. Moreover, the number of atoms of each element should be the same in the reactant and the product side. Now, let us balance each of the above reactions:
(A) This reaction represents an addition reaction as the nitrogen and hydrogen get combined together to form a single product that is ammonia. The reaction can be represented as:
\[{{N}_{2}}(g)+3{{H}_{2}}(g)\xrightarrow[773K]{catalyst}2N{{H}_{3}}(g)\]
(B) Since NaOH is a base and acetic acid is an acid, this reaction is a neutralization reaction that produces salt and water, and the reaction can be expressed as:
\[NaOH(aq)+C{{H}_{3}}COOH(aq)\to C{{H}_{3}}COONa(aq)+{{H}_{2}}O(l)\]
(C) When Ethanol Is warmed with ethanolic acid to form ethyl acetate in the presence of concentrated hydrochloric acid, then it is called an esterification reaction and it is an example of a double displacement reaction too. It can be represented as:
\[{{C}_{2}}{{H}_{5}}OH(l)+C{{H}_{3}}COOH(l)\xrightarrow{{{H}^{+}}}C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}(l)+{{H}_{2}}O(l)\]
(D) This reaction is an example of a combustion reaction, where, along with the desired product we get energy in the form of light and heat. The reaction is:
\[{{C}_{2}}{{H}_{4}}(g)+3{{O}_{2}}(g)\to 2C{{O}_{2}}(g)+2{{H}_{2}}O(g)+heat+light\]
Note: In the last reaction, which is a combustion reaction, since carbon is getting oxidized and oxygen is getting reduced, so we can also classify it as a redox reaction.
Complete step by step answer:
In order to answer our question, we need to learn about the laws of chemical combination. Now, we know that in any chemical reaction, energy can neither be created nor destroyed. The same applies to mass. Mass remains constant, i.e total mass of the reactants is equal to the mass of the products. Also, no new element can suddenly come out in the reaction. For example in the reaction of ${{H}_{2}}$ and ${{O}_{2}}$ to form ${{H}_{2}}O$, the only elements present are hydrogen and water. No new element like nitrogen has entered the reaction. Moreover, the number of atoms of each element should be the same in the reactant and the product side. Now, let us balance each of the above reactions:
(A) This reaction represents an addition reaction as the nitrogen and hydrogen get combined together to form a single product that is ammonia. The reaction can be represented as:
\[{{N}_{2}}(g)+3{{H}_{2}}(g)\xrightarrow[773K]{catalyst}2N{{H}_{3}}(g)\]
(B) Since NaOH is a base and acetic acid is an acid, this reaction is a neutralization reaction that produces salt and water, and the reaction can be expressed as:
\[NaOH(aq)+C{{H}_{3}}COOH(aq)\to C{{H}_{3}}COONa(aq)+{{H}_{2}}O(l)\]
(C) When Ethanol Is warmed with ethanolic acid to form ethyl acetate in the presence of concentrated hydrochloric acid, then it is called an esterification reaction and it is an example of a double displacement reaction too. It can be represented as:
\[{{C}_{2}}{{H}_{5}}OH(l)+C{{H}_{3}}COOH(l)\xrightarrow{{{H}^{+}}}C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}(l)+{{H}_{2}}O(l)\]
(D) This reaction is an example of a combustion reaction, where, along with the desired product we get energy in the form of light and heat. The reaction is:
\[{{C}_{2}}{{H}_{4}}(g)+3{{O}_{2}}(g)\to 2C{{O}_{2}}(g)+2{{H}_{2}}O(g)+heat+light\]
Note: In the last reaction, which is a combustion reaction, since carbon is getting oxidized and oxygen is getting reduced, so we can also classify it as a redox reaction.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Why Are Noble Gases NonReactive class 11 chemistry CBSE
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
At which age domestication of animals started A Neolithic class 11 social science CBSE
Which are the Top 10 Largest Countries of the World?
Give 10 examples for herbs , shrubs , climbers , creepers
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Write a letter to the principal requesting him to grant class 10 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE