Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

How do you write an equation of the line that passes through the points $\left( 4,3 \right)$ and $\left( -6,3 \right)$

seo-qna
Last updated date: 20th Jun 2024
Total views: 375.9k
Views today: 7.75k
Answer
VerifiedVerified
375.9k+ views
Hint: The equation of line is $y=mx+b$.
This is equation of a line in which is called as slope intercept form where $m$ is the slope and $b$ is the $y$-intercept for finding equations of line first we have to find $m$ slope and then use the slope to find the $y$-intercept. Then you can find the equation of line for finding slope use.
$m=\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}$ this formula. Then put the values in the equation. You will get the answer.

Complete step by step solution:
To point given $\left( 4,3 \right)$ and $\left( -6,3 \right)$
The equation of line is $y=mx+b$ where $m$ is the slope and $b$ is the $y$-intercept for finding equations of line first we have to find $m$ slope and then use the slope to find the $y$-intercept. Then you can find the equation of line for finding slope.
The formula for slope is $m=\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}$
$\left( {{x}_{1}}{{y}_{1}} \right)=\left( 4,3 \right)$ and $\left( {{x}_{2}},{{y}_{2}} \right)=\left( -6,3 \right)$
$m=\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}=\dfrac{-3-3}{-6-4}=\dfrac{-6}{-10}=\dfrac{3}{5}$
$m=\dfrac{3}{5}$
So, the slope of the line passing through the point $\left( 4,3 \right)$ and $\left( -6,-3 \right)$ is $3.$
Now we will use the slope to find the $y$intercept we know the slope of the line is $\dfrac{3}{5}$ we can put the value of slope $m$ in the equation of line in slope intercept from be,
$y=mx+b$
$\Rightarrow m=\dfrac{3}{5}$
$\Rightarrow y=\dfrac{3}{5}x+b$
Next choose one of the two points to put plug in for values of $x,y.$ It does not matter which one of the two points you should get the same answer in either case.
We will take $\left( x,y \right)$ $\left( 4:3 \right)$
Put this value in this equation.
$y=\dfrac{3}{5}x+b$
$\Rightarrow 3=\dfrac{3}{5}.4+b$
$\Rightarrow 3=\dfrac{12}{5}+b$
$\Rightarrow b=3-\dfrac{12}{5}$
$b=\dfrac{3}{5}$
Now, we have slope $m=\dfrac{3}{5}$ and the $y$-intercept $-b=\dfrac{3}{5}$
Put this value in the equation of the line in slope intercept form is
$y=\dfrac{3}{5}x+\dfrac{3}{5}$

Additional Information:
Slope intercept equation of vertical and horizontal lines. The equation of vertical lines is $x=b$ Since a vertical goes straight point on a vertical line is the same. Therefore whatever the $x$ value is also the value of $b.$
For instance the red line in the picture below is graph of the $x=1$
The equation of a horizontal line is $0$ is the general formula for the standard equation $y=mx+b$ becomes ${{y}_{0}}x+b$ $y=b$
Also since the line horizontal every point on that line has the same $y$ value. The $y$ value is therefore also the $y$ intercept for instance the red line.

Note: While solving this type of problem also slope intercept it is easy to solve.
Use the correct formula for students making mistakes on slope formulas.
It is $m=\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}$ students write $\dfrac{{{x}_{2}}-{{x}_{1}}}{{{y}_{2}}-{{y}_{1}}}$
Sometimes so write carefully.