
Which one of the following species is diamagnetic in nature?
(a) $He_{2}^{+}$
(b) ${{H}_{2}}$
(c) $H_{2}^{+}$
(d) $H_{2}^{-}$
Answer
445.5k+ views
Hint: Diamagnetic species are those species that consist of the paired electrons and to find it, first of all, you should know how many electrons are present in each of the above-given species and then, from that, you can easily recognize the species having paired electrons in their valence shell. Now solve it.
Complete step by step answer:
First of all, let’s discuss what are diamagnetic species. Diamagnetic species are those species that do not have any paired electrons in their valence shell and such substances or the species are weakly repelled by the magnet when placed in the magnetic field.
Now consider the statement as:
First, we will calculate the number of electrons present in each of the given species and then, we can easily identify which of them is a diamagnetic species.
So, thus, from the above table, we come to know that ${{H}_{2}}$ is a diamagnetic species.
So, the correct answer is “Option B”.
Note: Don’t get confused in the paramagnetic and diamagnetic substances.
By the diamagnetic species or substances we simply, mean the absence of the unpaired electrons, and such species are weakly repelled by the magnetic.
- While on the other hand by the paramagnetic substances, we mean the presence of the unpaired electron, and substances are strongly attracted towards the magnetic when they are placed in three magnetic fields.
Complete step by step answer:
First of all, let’s discuss what are diamagnetic species. Diamagnetic species are those species that do not have any paired electrons in their valence shell and such substances or the species are weakly repelled by the magnet when placed in the magnetic field.
Now consider the statement as:
First, we will calculate the number of electrons present in each of the given species and then, we can easily identify which of them is a diamagnetic species.
Species | No. of electrons present | Paired/unpaired | Paramagnetic/diamagnetic |
$He_{2}^{+}$ | Three | unpaired | Paramagnetic |
${{H}_{2}}$ | Two | Paired | diamagnetic |
$H_{2}^{+}$ | One | Unpaired | Paramagnetic |
$H_{2}^{-}$ | Three | Unpaired | Paramagnetic |
So, thus, from the above table, we come to know that ${{H}_{2}}$ is a diamagnetic species.
So, the correct answer is “Option B”.
Note: Don’t get confused in the paramagnetic and diamagnetic substances.
By the diamagnetic species or substances we simply, mean the absence of the unpaired electrons, and such species are weakly repelled by the magnetic.
- While on the other hand by the paramagnetic substances, we mean the presence of the unpaired electron, and substances are strongly attracted towards the magnetic when they are placed in three magnetic fields.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

The correct geometry and hybridization for XeF4 are class 11 chemistry CBSE

Water softening by Clarks process uses ACalcium bicarbonate class 11 chemistry CBSE

With reference to graphite and diamond which of the class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

State and prove Bernoullis theorem class 11 physics CBSE

What organs are located on the left side of your body class 11 biology CBSE

How many valence electrons does nitrogen have class 11 chemistry CBSE
