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**Hint:**In order to solve this question we see the digit at the end will be the largest digit if you check the digit in the tens place of each number before arranging in ascending order. The largest number will then be the one with the largest digit.

**Complete step by step solution:**We must determine the highest number in the given situation. The current set of numbers is as follows:

200 , 220 , 450 , 555

So, in order to obtain the largest number, we must examine the digit at the hundreds place and find the largest digit.

So, as shown below, we shall arrange the tens digits of each integer in ascending order:

Arranging in ascending order according to hundred digit

450<555

Check for the tens place if two numbers share the same digit at the hundred place. The maximum number will be determined by the largest digit in the one place, followed by the largest digit in the tens place.So 220 and 200 have same tens digit so we will check tens digit

Hundred digit of each integer : 200 is 2 , 220 is 2 , 450 is 4 and 555 is 5

So, as shown below, we shall arrange the tens digits of each integer in ascending order:

200<220

The largest digit is therefore 5. The numbers will then be arranged in the following ascending order:

200 < 220<450<555

The largest number in the provided set of numbers is therefore 555

**Option ‘D’ is correct**

**Note:**To find the greatest number in the given set the numbers can also be arranged in ascending order, with the number at the right end being the highest number and to find the lowest number in the given set the numbers can also be arranged in descending order, with the number at the right end being the highest number

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