
Which of the following will exhibit maximum ionic conductivity?
A. ${{K}_{4}}[Fe{{(CN)}_{6}}]$
B. $[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}$
C. $[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}$
D. $[Ni{{(CO)}_{4}}]$
Answer
540.9k+ views
Hint: The molar conductivity of a coordination compound is going to depend on the number of ions produced by the respective coordination compound when it is dissolved in water. If the coordination compound forms a high number of ions after adding to the water then the molar conductivity of the respective compound will be high.
Complete step by step answer:
- In the question, it is asked to find the coordination compound which exhibits maximum molar conductivity among the given options.
- Coming to the given options. Option A, ${{K}_{4}}[Fe{{(CN)}_{6}}]$.
-The compound ${{K}_{4}}[Fe{{(CN)}_{6}}]$ dissolves in water and forms the ions and we can see them in the below chemical equation.
\[{{K}_{4}}[Fe{{(CN)}_{6}}]\to 4{{K}^{+}}+{{[Fe{{(CN)}_{6}}]}^{4-}}\]
- In the above chemical equation we can see clearly that there are five ions formed after dissociation of the compound ${{K}_{4}}[Fe{{(CN)}_{6}}]$.
- Coming to option B, $[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}$.
- The compound $[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}$ dissolves in water and forms the ions and we can see them in the below chemical equation.
\[[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}\to {{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}+3C{{l}^{-}}\]
- In the above chemical equation we can see clearly that there are four ions are formed after dissociation of the compound $[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}$.
- Coming to the option C, $[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}$.
- The compound $[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}$ dissolves in water and forms the ions and we can see them in the below chemical equation.
\[[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}\to {{[Cu{{(N{{H}_{3}})}_{4}}]}^{2+}}+2C{{l}^{-}}\]
- In the above chemical equation we can see clearly that there are three ions are formed after dissociation of the compound $[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}$.
- Coming to the option D, $[Ni{{(CO)}_{4}}]$. It does not dissolve in water due to the absence of the polarity nature then it will be a single molecule in water.
- There the compound A, ${{K}_{4}}[Fe{{(CN)}_{6}}]$ shows maximum molar conductivity due to the formation of 5 ions when dissolved in water. So, the correct answer is “Option A”.
Note: The number of ions formed by a coordination compound is going to decide the molar conductivity of the particular coordination compound. The number of ions formed by a coordination compound is directly proportional to the molar conductivity of the solution.
Complete step by step answer:
- In the question, it is asked to find the coordination compound which exhibits maximum molar conductivity among the given options.
- Coming to the given options. Option A, ${{K}_{4}}[Fe{{(CN)}_{6}}]$.
-The compound ${{K}_{4}}[Fe{{(CN)}_{6}}]$ dissolves in water and forms the ions and we can see them in the below chemical equation.
\[{{K}_{4}}[Fe{{(CN)}_{6}}]\to 4{{K}^{+}}+{{[Fe{{(CN)}_{6}}]}^{4-}}\]
- In the above chemical equation we can see clearly that there are five ions formed after dissociation of the compound ${{K}_{4}}[Fe{{(CN)}_{6}}]$.
- Coming to option B, $[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}$.
- The compound $[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}$ dissolves in water and forms the ions and we can see them in the below chemical equation.
\[[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}\to {{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}+3C{{l}^{-}}\]
- In the above chemical equation we can see clearly that there are four ions are formed after dissociation of the compound $[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}$.
- Coming to the option C, $[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}$.
- The compound $[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}$ dissolves in water and forms the ions and we can see them in the below chemical equation.
\[[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}\to {{[Cu{{(N{{H}_{3}})}_{4}}]}^{2+}}+2C{{l}^{-}}\]
- In the above chemical equation we can see clearly that there are three ions are formed after dissociation of the compound $[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}$.
- Coming to the option D, $[Ni{{(CO)}_{4}}]$. It does not dissolve in water due to the absence of the polarity nature then it will be a single molecule in water.
- There the compound A, ${{K}_{4}}[Fe{{(CN)}_{6}}]$ shows maximum molar conductivity due to the formation of 5 ions when dissolved in water. So, the correct answer is “Option A”.
Note: The number of ions formed by a coordination compound is going to decide the molar conductivity of the particular coordination compound. The number of ions formed by a coordination compound is directly proportional to the molar conductivity of the solution.
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