Answer
Verified
437.7k+ views
Hint: Oxidation number also known as oxidation state is defined as the total number of electrons which an atom either gain or loses to form a chemical bond with other atom or we can say that the oxidation number is the charge an atom would get if the compound were made up of ions.
Complete step by step solution:
Let’s find the oxidation state in each of the given option:
Oxidation state of S in ${{(N{{H}_{4}})}_{2}}{{S}_{2}}{{O}_{8}}$
Oxidation state of $N{{H}_{4}}$ ion in the given compound= +1
Oxidation state of O in the given compound= -2
Oxidation state of the sulphur=\[2(1)+2x+8(-2)=0\]
\[2+2x-16=0\]
x = +7
Oxidation state of Os in$Os{{O}_{4}}$ is +8
Oxidation state of O in the given compound= -2
Oxidation state of the Os = $x+4(-2)=0$
x = +8
Oxidation state of S in ${{H}_{2}}S{{O}_{5}}$ is +8
Oxidation state of H in the given compound= +1
Oxidation state of O in the given compound= -2
Oxidation state of the sulphur = $2(1)+x+5(-2)=0$
x = +8
Oxidation state of O in$K{{O}_{2}}$ is -$\dfrac{1}{2}$
Oxidation state of K in the given compound= +1
Oxidation state of O = $1+2x=0$
x = -$\dfrac{1}{2}$
Hence the incorrect statement is option (A)
Note: The oxidation number of an atom in the neutral material containing atoms of only one type of element is zero. Which means that the oxidation number of ${{O}_{2}},{{O}_{3}},{{P}_{4}}$ etc. is zero.. The number of simple ions oxidizing is equal to the charge on the ion, and in a neutral compound the sum of the oxidation state of all the elements is zero.
Complete step by step solution:
Let’s find the oxidation state in each of the given option:
Oxidation state of S in ${{(N{{H}_{4}})}_{2}}{{S}_{2}}{{O}_{8}}$
Oxidation state of $N{{H}_{4}}$ ion in the given compound= +1
Oxidation state of O in the given compound= -2
Oxidation state of the sulphur=\[2(1)+2x+8(-2)=0\]
\[2+2x-16=0\]
x = +7
Oxidation state of Os in$Os{{O}_{4}}$ is +8
Oxidation state of O in the given compound= -2
Oxidation state of the Os = $x+4(-2)=0$
x = +8
Oxidation state of S in ${{H}_{2}}S{{O}_{5}}$ is +8
Oxidation state of H in the given compound= +1
Oxidation state of O in the given compound= -2
Oxidation state of the sulphur = $2(1)+x+5(-2)=0$
x = +8
Oxidation state of O in$K{{O}_{2}}$ is -$\dfrac{1}{2}$
Oxidation state of K in the given compound= +1
Oxidation state of O = $1+2x=0$
x = -$\dfrac{1}{2}$
Hence the incorrect statement is option (A)
Note: The oxidation number of an atom in the neutral material containing atoms of only one type of element is zero. Which means that the oxidation number of ${{O}_{2}},{{O}_{3}},{{P}_{4}}$ etc. is zero.. The number of simple ions oxidizing is equal to the charge on the ion, and in a neutral compound the sum of the oxidation state of all the elements is zero.
Recently Updated Pages
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Which one of the following places is not covered by class 10 social science CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Give 10 examples for herbs , shrubs , climbers , creepers
Why is there a time difference of about 5 hours between class 10 social science CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
What is BLO What is the full form of BLO class 8 social science CBSE