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Last updated date: 04th Dec 2023
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# Which of the following is most polar?(A)(B)(C)(D)

The compound given in the first option has $12\pi {e^ - }$ and it is antiaromatic. If we break a bond, we get a compound with charges. Now, we can observe that the compound is not aromatic and because of this reason it is not most polar. If we break a bond in the compound given in the second option, we get a compound with charges and all the rings in the compound are aromatic. It is said to be a quasi-aromatic compound. So, it is the most stable compound. We cannot break any bond in the third compound, because both the rings are aromatic and they are stable. So, polarity cannot be generated in this compound. The compound in the fourth option has two aromatic rings. So, this compound also will not allow the breaking of bonds as they are already stable. So, polarity cannot be generated in this compound also.