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Which of the following ions or compounds in a solution tend to produce an acidic, a basic or neutral solution?
i.${{C}_{2}}{{H}_{5}}{{O}^{-}}$
ii.$C{{u}^{2+}}$
iii.$S{{O}_{3}}^{2-}$
iv.${{F}^{-}}$
v.$N{{H}_{4}}^{+}$
vi.$C{{H}_{3}}COONa$
vii.$KN{{O}_{3}}$
viii.$NaOCl$
ix.$N{{a}_{2}}C{{O}_{3}}$
x.$ZnC{{l}_{2}}$


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Last updated date: 20th Jul 2024
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Answer
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Hint: The nature of solutions depends upon the nature of the salt which is dissolved in it. The term solution is often applied to the liquid state of matter, but solutions of gases and solids are possible.

Complete answer:
a. ${{C}_{2}}{{H}_{5}}{{O}^{-}}$ is acidic in nature. Ethanol isn't a base because it's not an example of a compound, which has an acidic nature. It doesn't give $O{{H}^{-}}$ ions within the solution. When acid is added to water, the molecules of acid dissociate to create ions. So the solution will be acidic in nature.
b. As the oxidation state is Cu is 2+ it is expected to be basic in nature. Therefore the solution will be basic in nature.
c. $S{{O}_{3}}^{-}$ is acidic in nature so the solution will also be acidic in nature.
d. The fluoride ion acts as a weak Bronsted-Lowry base. The hydroxide ion that is produced in the above reaction makes the solution slightly basic. Salt hydrolysis is a reaction where one of the ions from a salt reacts with water, resulting in either an acidic or basic solution.
e. Ammonium ion is basic in nature so the solution is also basic in nature.
f. Sodium acetate (CH3COONa) is a salt in solid state which can not be used in anhydrous or liquid form as an acid or base. Now, as NaOH is a strong base and $C{{H}_{3}}COOH$ is a weak acid, the resulting solution will be basic in nature. Sodium acetate is therefore used in an aqueous medium.
g. Potassium nitrate ( $KN{{O}_{3}}$ ) is neither an acid or base so it is neutral and eventually the solution is also neutral.
h. $NaOCl$ is a salt, which dissolves completely in water, to give $N{{a}^{+}}$ and $Cl{{O}^{-}}$. Hypochlorite, $Cl{{O}^{-}}$, is a conjugate base of the weak acid, HClO. So, this is a weak base solution so it will be basic in nature.
I.$N{{a}_{2}}C{{O}_{3}}$ is a salt composed of strong base Na and weak acid carbonate . So the solution will be basic in nature.
J.HCl being a strong acid, Zinc chloride is acidic in nature and so is the solution.

Note: Solution, in chemistry, the same or homogeneous mixture of two or more substances in relative amounts that may be varied continuously up to what's called the limit of solubility.