
Which of the following compounds are chiral and resolvable?
A. $ \left[ {{C}_{6}}{{H}_{5}}{{N}^{+}}\left( C{{H}_{2}}C{{H}_{2}}C{{H}_{3}} \right)\left( {{C}_{2}}{{H}_{5}} \right)\left( C{{H}_{3}} \right)B{{r}^{-}} \right] $
B. $ {{C}_{6}}{{H}_{5}}N\left( C{{H}_{3}} \right)\left( {{C}_{2}}{{H}_{5}} \right) $
C. $ C{{H}_{3}}C{{H}_{2}}CH\left( C{{H}_{3}} \right)N\left( C{{H}_{3}} \right)\left( {{C}_{2}}{{H}_{5}} \right) $
D.
Answer
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Hint :Chiral molecule is a molecule which consists of one or more carbon atom that has four different or non-identical substituents, and such carbon atoms are called a chiral center or a stereogenic center or a stereocenter while, the molecules which are not superimposable on their mirror image are also called chiral molecule. The property of non-superimposability of a molecule on its mirror image is called chirality.
Complete Step By Step Answer:
A resolvable compound is a compound that is optically active, while a compound which is capable of optical rotation is called optically active. All pure chiral compounds are optically active.
Option (a) is a chiral and resolvable compound because the compound has a non-superimposable mirror image.
In Option (b) due to rapid pyramidal inversion the tertiary amine will always remain in the form of racemic mixture. Therefore, it is optically inactive.
Option (c) is a chiral and resolvable compound because the third carbon atom has four different substituents i.e. ethyl, methyl, hydrogen and a nitrogen moreover, the compound has non-superimposable mirror image.
Option (d) bulker groups are present which would repel on being rotated so rotation would not occur so this compound is optically inactive. Moreover, no carbon atom has four different substituents hence the compound is not chiral.
The correct answer is option A and C.
Note :
Stereoisomers are the isomers which have the same position of atoms or groups but they differ in the spatial arrangement around the central atom.
The stereoisomers which are not mirror images of each other are called diastereomers and a meso compound is one whose molecules are superimposable on their mirror images even though they contain chiral centres.
Complete Step By Step Answer:
A resolvable compound is a compound that is optically active, while a compound which is capable of optical rotation is called optically active. All pure chiral compounds are optically active.
Option (a) is a chiral and resolvable compound because the compound has a non-superimposable mirror image.
In Option (b) due to rapid pyramidal inversion the tertiary amine will always remain in the form of racemic mixture. Therefore, it is optically inactive.
Option (c) is a chiral and resolvable compound because the third carbon atom has four different substituents i.e. ethyl, methyl, hydrogen and a nitrogen moreover, the compound has non-superimposable mirror image.
Option (d) bulker groups are present which would repel on being rotated so rotation would not occur so this compound is optically inactive. Moreover, no carbon atom has four different substituents hence the compound is not chiral.
The correct answer is option A and C.
Note :
Stereoisomers are the isomers which have the same position of atoms or groups but they differ in the spatial arrangement around the central atom.
The stereoisomers which are not mirror images of each other are called diastereomers and a meso compound is one whose molecules are superimposable on their mirror images even though they contain chiral centres.
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