
Which of the following amines can be prepared by Gabriel phthalimide reaction?
A. neopentylamine
B. n-butylamine
C. triethylamine
D. t-butylamine
Answer
555.3k+ views
Hint: The phthalimide gives nucleophilic substitution with an alkyl halide to form primary amines. We will find the primary amine. The primary amine will have nitrogen attached with only one carbon and two hydrogens. The amine should not be hindered because hindered amine are not formed by Gabriel’s Phthalimide synthesis.
Complete Step by step answer: Gabriel’s Phthalimide synthesis is used for the conversion of primary alkyl halide into a primary amine.
In Gabriel phthalimide synthesis, a base abstract proton from phthalimide gives a nucleophile phthalimide ion which attacks on the unhindered primary alkyl halide. The base hydrolysis of alkylated phthalimide gives the primary unhindered amine and phthalimide ion.
Phthalimide ion itself is a bulky ion, so it prefers attack on hindered alkyl halide.
A general reaction is as follows:
We will draw the structures of all amine and find the primary unhindered amine as follows:
The triethylamine is not primary amine so it will not be prepared by Gabriel’s Phthalimide synthesis. Neo-pentylamine, n-butylamine, and t-butylamine are primary but neopentylamine, and t-butylamine are hindered amines, so only n-butylamine can be prepared by Gabriel’s Phthalimide synthesis.
Therefore option (B) n-butylamine, is correct.
Note: Gabriel’s Phthalimide synthesis is not used for the preparation of secondary, tertiary aliphatic amines due to steric hindrance. This method is also not used for the preparation of aromatic amines. Gabriel phthalimide synthesis nucleophilic substitution reaction. The general reaction shown by aromatic halide is the electrophilic substitution reaction. Because aromatic halide shows resonance due to resonance they are stable. The nucleophilic substitution destabilizes the resonance of the aromatic compounds.
Complete Step by step answer: Gabriel’s Phthalimide synthesis is used for the conversion of primary alkyl halide into a primary amine.
In Gabriel phthalimide synthesis, a base abstract proton from phthalimide gives a nucleophile phthalimide ion which attacks on the unhindered primary alkyl halide. The base hydrolysis of alkylated phthalimide gives the primary unhindered amine and phthalimide ion.
Phthalimide ion itself is a bulky ion, so it prefers attack on hindered alkyl halide.
A general reaction is as follows:
We will draw the structures of all amine and find the primary unhindered amine as follows:
The triethylamine is not primary amine so it will not be prepared by Gabriel’s Phthalimide synthesis. Neo-pentylamine, n-butylamine, and t-butylamine are primary but neopentylamine, and t-butylamine are hindered amines, so only n-butylamine can be prepared by Gabriel’s Phthalimide synthesis.
Therefore option (B) n-butylamine, is correct.
Note: Gabriel’s Phthalimide synthesis is not used for the preparation of secondary, tertiary aliphatic amines due to steric hindrance. This method is also not used for the preparation of aromatic amines. Gabriel phthalimide synthesis nucleophilic substitution reaction. The general reaction shown by aromatic halide is the electrophilic substitution reaction. Because aromatic halide shows resonance due to resonance they are stable. The nucleophilic substitution destabilizes the resonance of the aromatic compounds.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Discuss the various forms of bacteria class 11 biology CBSE

