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# ${\text{What is the value of (}}{\cos ^2}{67^ \circ }{\text{ - }}{\sin ^2}{23^ \circ })?$  Answer Verified
$Given{\text{ equation is (}}{\cos ^2}{67^ \circ }{\text{ - }}{\sin ^2}{23^ \circ }) \\ Now,{\text{ we can write this equation in this form i}}{\text{.e}} \\ = {\cos ^2}({90^ \circ }{\text{ - 2}}{{\text{3}}^ \circ }{\text{) - }}{\sin ^2}{23^ \circ } \\ {\text{We know that}} \\ {\cos ^2}({90^ \circ }{\text{ - }}\theta ){\text{ = }}{\sin ^2}\theta \\ {\text{Now using this concept we can write the above equation in this form}} \\ {\text{i}}{\text{.e}} \\ {\text{ = }}{\sin ^2}{23^ \circ }{\text{ - }}{\sin ^2}{23^ \circ } \\ = {\text{ 0}} \\ {\text{Note: - These type of problems can be solved by converting either }}\cos \theta {\text{ into }}\sin \theta {\text{ or }}\sin \theta {\text{ into }}\cos \theta \\ {\text{here we have converted }}\cos \theta {\text{ into }}\sin \theta {\text{ in the similar way we can do it for other questions as well}}{\text{.}} \\ {\text{ }} \\$
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