Vertex of a square is at the origin and it’s one side lies along the line \[3x - 4y - 10 = 0\]. Find the area of the square.
Answer
603k+ views
Hint: For finding the area of the square, distance is calculated from origin to line $3x - 4y - 10 = 0$ . This will be the side of the square. Once you know the side length, square it to get the area of the square, as the area of the square is square of its side length.
Complete step by step answer:
Let us start the solution to the above question by drawing a representative diagram of the situation given in the question.
As one of the sides of the square is \[3x - 4y - 10 = 0\] and origin does not lie on this line but the origin is one of the vertices. So, the origin must lie on the opposite side and the distance of the origin from the given line is equal to the side length of the square.
The same can be seen from the diagram also, that AB is one of the sides of the square and is the distance between the origin and the line BC whose equation is \[3x - 4y - 10 = 0\].
Now to find the length of the side AB, we will use the formula of the perpendicular distance of a point from a line.
We know that the distance of the point $\left( {{x_1},{y_1}} \right)$ from the line \[ax + by + c = 0\] is $\left| {\dfrac{{a{x_1} + b{y_1} + c}}{{\sqrt {{a^2} + {b^2}} }}} \right|$.
Therefore, the perpendicular distance of $\left( {0,0} \right)$ from \[3x - 4y - 10 = 0\] is:
$ \Rightarrow $ $\left| {\dfrac{{a{x_1} + b{y_1} + c}}{{\sqrt {{a^2} + {b^2}} }}} \right|$$ = \left| {\dfrac{{ - 10}}{{\sqrt {{3^2} + {4^2}} }}} \right| = \dfrac{{10}}{{\sqrt {25} }} = \dfrac{{10}}{5} = 2$
So, the side length of the square is $2$ units. We know that the area of the square is equal to the square of its side.
Area of the square$ = {a^2} = {2^2} = 4$ square unit
Therefore, the area of the square is $4$ square units.
Note:
The solution can be done by an alternative method, you can use the equation of the line $3x - 4y - 10 = 0$ to get the equation of the perpendicular line using the point that the product of the slopes of a perpendicular line is $ - 1$ and passing through the origin. After getting the perpendicular equation, find the point of intersection. Calculate the distance between two points to get the length of the square.
Complete step by step answer:
Let us start the solution to the above question by drawing a representative diagram of the situation given in the question.
As one of the sides of the square is \[3x - 4y - 10 = 0\] and origin does not lie on this line but the origin is one of the vertices. So, the origin must lie on the opposite side and the distance of the origin from the given line is equal to the side length of the square.
The same can be seen from the diagram also, that AB is one of the sides of the square and is the distance between the origin and the line BC whose equation is \[3x - 4y - 10 = 0\].
Now to find the length of the side AB, we will use the formula of the perpendicular distance of a point from a line.
We know that the distance of the point $\left( {{x_1},{y_1}} \right)$ from the line \[ax + by + c = 0\] is $\left| {\dfrac{{a{x_1} + b{y_1} + c}}{{\sqrt {{a^2} + {b^2}} }}} \right|$.
Therefore, the perpendicular distance of $\left( {0,0} \right)$ from \[3x - 4y - 10 = 0\] is:
$ \Rightarrow $ $\left| {\dfrac{{a{x_1} + b{y_1} + c}}{{\sqrt {{a^2} + {b^2}} }}} \right|$$ = \left| {\dfrac{{ - 10}}{{\sqrt {{3^2} + {4^2}} }}} \right| = \dfrac{{10}}{{\sqrt {25} }} = \dfrac{{10}}{5} = 2$
So, the side length of the square is $2$ units. We know that the area of the square is equal to the square of its side.
Area of the square$ = {a^2} = {2^2} = 4$ square unit
Therefore, the area of the square is $4$ square units.
Note:
The solution can be done by an alternative method, you can use the equation of the line $3x - 4y - 10 = 0$ to get the equation of the perpendicular line using the point that the product of the slopes of a perpendicular line is $ - 1$ and passing through the origin. After getting the perpendicular equation, find the point of intersection. Calculate the distance between two points to get the length of the square.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

