# What is the value when 44 is increased by 12.5%.

Last updated date: 30th Mar 2023

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Answer

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Hint: Try to calculate the increment and use basic arithmetic.

Percent means parts by 100. It is the ratio in which the denominator is $100$.

So $x\% $ is given by $\dfrac{x}{{100}}$.

In the above problem we need to increase the number by $12.5\% $.

Increment of numbers means increasing its value or adding another positive real number to its value.

Hence, we need to find the number or the value by which $44$ is to be increased.

Since in the problem, the increment percentage is given, first we need to find the given percent of $44$.

Using the above-mentioned rule, $12.5\% = \dfrac{{12.5}}{{100}}$.

Therefore, $12.5\% $of $44$is given by

$\dfrac{{12.5}}{{100}} \times 44 = \dfrac{{550}}{{100}} = 5.5$

Increasing $44$by $5.5 \Rightarrow 44 + 5.5 = 49.5$

Hence Value of $44$ is increased by $12.5\% $ is equal to $49.5$.

Or

The above-mentioned procedure could be formed into a formula as

Value$ = Original\,Number\left( {1 + \dfrac{x}{{100}}} \right)$ ,where $x$ is the percent to be increased.

In this problem, $Original{\text{ }}Number = 44$ and $x = 12.5$

Using in the above-mentioned formula, we get,

Value$ = 44\left( {1 + \dfrac{{12.5}}{{100}}} \right) = 44\left( {1 + \dfrac{1}{8}} \right) = 44 \times \dfrac{9}{8} = 49.5$.

Hence the answer is $49.5$.

Note: Percent always means out of hundred. Increment or decrement can be done using the same method as explained above with slight modification for decrement.

Percent means parts by 100. It is the ratio in which the denominator is $100$.

So $x\% $ is given by $\dfrac{x}{{100}}$.

In the above problem we need to increase the number by $12.5\% $.

Increment of numbers means increasing its value or adding another positive real number to its value.

Hence, we need to find the number or the value by which $44$ is to be increased.

Since in the problem, the increment percentage is given, first we need to find the given percent of $44$.

Using the above-mentioned rule, $12.5\% = \dfrac{{12.5}}{{100}}$.

Therefore, $12.5\% $of $44$is given by

$\dfrac{{12.5}}{{100}} \times 44 = \dfrac{{550}}{{100}} = 5.5$

Increasing $44$by $5.5 \Rightarrow 44 + 5.5 = 49.5$

Hence Value of $44$ is increased by $12.5\% $ is equal to $49.5$.

Or

The above-mentioned procedure could be formed into a formula as

Value$ = Original\,Number\left( {1 + \dfrac{x}{{100}}} \right)$ ,where $x$ is the percent to be increased.

In this problem, $Original{\text{ }}Number = 44$ and $x = 12.5$

Using in the above-mentioned formula, we get,

Value$ = 44\left( {1 + \dfrac{{12.5}}{{100}}} \right) = 44\left( {1 + \dfrac{1}{8}} \right) = 44 \times \dfrac{9}{8} = 49.5$.

Hence the answer is $49.5$.

Note: Percent always means out of hundred. Increment or decrement can be done using the same method as explained above with slight modification for decrement.

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