
Ullmann reaction is given by:
(A) $ {C_6}{H_5} - Cl $
(B)
(C)
(D)
Answer
510k+ views
Hint: We know that the Ullmann reaction, also known as Ullmann coupling is an organic reaction in which two aryl halides are coupled in the presence of copper to produce a bi aryl as a result. Fritz Ullmann, a German chemist, is the name given to this coupling reaction.
Complete answer:
Step 1: The Ullmann reaction entails the creation of an active copper(I) species when an excess of metallic copper is introduced to the aryl halide at moderately high temperatures, that is >200 degree Celsius.
Step 2: Another haloarene molecule is oxidatively added to this copper(I) species, forming a bond between the two molecules
Step 3: The copper compound formed by the two aryl halide molecules is reductively eliminated in the final step of the Ullmann reaction process, resulting in the forming of a new carbon-carbon bond between the two aryl compounds.
That is, ortho and para nitro derivatives of halo benzene, as well as those halo benzenes with deactivating groups at the ortho and nitro sites, are used in Ullmann's reaction. As a result, Option "D" is the right solution.
Note:
Applications of the Ullmann Reaction are:
1. Ullmann Reaction Applications Biphenylenes can be made from 2,2-iodophenyl using the Ullmann reaction.
2. This reaction can be used to close five-membered rings as well.
3. When one of the reactants is provided in abundance, an unsymmetrical reaction can be achieved.
4. This reaction will couple chiral reactants into chiral products.
Complete answer:
Step 1: The Ullmann reaction entails the creation of an active copper(I) species when an excess of metallic copper is introduced to the aryl halide at moderately high temperatures, that is >200 degree Celsius.
Step 2: Another haloarene molecule is oxidatively added to this copper(I) species, forming a bond between the two molecules
Step 3: The copper compound formed by the two aryl halide molecules is reductively eliminated in the final step of the Ullmann reaction process, resulting in the forming of a new carbon-carbon bond between the two aryl compounds.
That is, ortho and para nitro derivatives of halo benzene, as well as those halo benzenes with deactivating groups at the ortho and nitro sites, are used in Ullmann's reaction. As a result, Option "D" is the right solution.
Note:
Applications of the Ullmann Reaction are:
1. Ullmann Reaction Applications Biphenylenes can be made from 2,2-iodophenyl using the Ullmann reaction.
2. This reaction can be used to close five-membered rings as well.
3. When one of the reactants is provided in abundance, an unsymmetrical reaction can be achieved.
4. This reaction will couple chiral reactants into chiral products.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Difference Between Prokaryotic Cells and Eukaryotic Cells

