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**Hint:**Tension is defined in physics as the pulling force conveyed axially by a thread, cable, cord, or other one-dimensional continuous component, or by each end of a pole, truss member, or other three-dimensional object; tension may also be defined as the action-reaction pair of forces acting at each end of such elements. Tension can be thought of as the polar opposite of compression.

**Complete step by step answer:**

A pulse is a term used in physics to describe a single disturbance moving through a propagation medium. This medium could be a vacuum (in the case of electromagnetic radiation) or matter, and it could be infinite or finite in size.

Given, \[{{\rm{m}}_{\rm{A}}} = 1.2 \times {10^{ - 2}}\;{\rm{kg}}/{\rm{m}}\]

\[{{\bf{T}}_{\bf{A}}} = {\bf{4}}.{\bf{8N}} \\ \]

\[ \Rightarrow {{\bf{V}}_{\rm{A}}} = \sqrt {{\rm{T}}/{\rm{m}}} = {\bf{20m}}/{\rm{s}} \\ \]

\[\Rightarrow {{\rm{m}}_{\rm{B}}} = 1.2 \times {10^{ - 2}}\;{\rm{kg}}/{\rm{m}} \\\]

\[\Rightarrow {{\rm{T}}_{\rm{B}}} = 7.5\;{\rm{N}} \\\]

\[ \Rightarrow {{\rm{V}}_{\rm{B}}} = \sqrt {{\rm{T}}/{\rm{m}}} \\

\Rightarrow {{\rm{V}}_{\rm{B}}}= {\bf{25\,m}}/{\rm{s}}\]

On string $A$ at $t = 0$

\[{{\rm{t}}_1} = 0 + 20\;{\rm{ms}} = 20 \times {10^{ - 3}} = 0.02\,{\rm{sec}}\]

In 0.02 sec, $A$ has travelled 20 × 0.02 = 0.4m = s

Relative speed between $A$ and $B$ =25−20 = 5m/s = v

Time taken for B to overtake A:

\[\text{Time} = \dfrac{s}{v}\]

\[\Rightarrow \text{Time}= \dfrac{{0.4}}{5}\]

\[\therefore \text{Time}= 0.8\,sec\]

**Note:**When atoms or molecules are pulled apart and gain potential energy while a restoring force is still present, the restoring force will cause stress. In order to return the string/rod to its relaxed length, each end of a string or rod under a certain strain could tug on the object it is attached to.

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