Answer
384k+ views
Hint: Just like any other numerical problem, firstly, you could note down all the given values. Then you could recall Coulomb’s law. After recalling, you could substitute all the given values into the expression for Coulomb’s law. Then, you could rearrange this expression to get the required magnitude of charge.
Formula used:
Coulomb’s law,
$F=k\dfrac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}$
Complete answer:
In the question, we are given two charges that are identical in both sign and magnitude that are separated by 50meters. Since these charges are of the same sign, quite obviously the force experienced by them would be repulsive and the magnitude of this repulsive force is given as 144N. Using all this information, we are supposed to find the magnitude of this charge in units of micro-coulombs.
In order to answer this question, let us recall Coulomb’s law. The statement of this law goes like this. The force between two charges separated by a certain distance is found to be proportional to the product of the charges and inversely proportional to the distance that separates them. Mathematically,
$F=k\dfrac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}$
Here, k acts as the proportionality constant.
In the given question,
${{q}_{1}}={{q}_{2}}=q$
Substituting all the given values,
$144=9\times {{10}^{9}}\times \dfrac{{{q}^{2}}}{{{50}^{2}}}$
$\Rightarrow {{q}^{2}}=\dfrac{144\times 2500}{9\times {{10}^{9}}}$
$\Rightarrow q=0.63245\times {{10}^{-2}}C$
$\therefore q=6324.5\mu C$
Therefore, we found the magnitude of the charge in microcoulombs to be$q=6324.5\mu C$.
Note:
You may have noticed the proportionality constant that we introduced in the coulomb’s law. This constant is known to have a value given by,
$k=\dfrac{1}{4\pi {{\varepsilon }_{0}}}=9\times {{10}^{9}}N{{C}^{-2}}{{m}^{2}}$
Though there is no mention of signs in the solution, it does have significance. Taking the product will cancel the sign out when they are like charges.
Formula used:
Coulomb’s law,
$F=k\dfrac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}$
Complete answer:
In the question, we are given two charges that are identical in both sign and magnitude that are separated by 50meters. Since these charges are of the same sign, quite obviously the force experienced by them would be repulsive and the magnitude of this repulsive force is given as 144N. Using all this information, we are supposed to find the magnitude of this charge in units of micro-coulombs.
In order to answer this question, let us recall Coulomb’s law. The statement of this law goes like this. The force between two charges separated by a certain distance is found to be proportional to the product of the charges and inversely proportional to the distance that separates them. Mathematically,
$F=k\dfrac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}$
Here, k acts as the proportionality constant.
In the given question,
${{q}_{1}}={{q}_{2}}=q$
Substituting all the given values,
$144=9\times {{10}^{9}}\times \dfrac{{{q}^{2}}}{{{50}^{2}}}$
$\Rightarrow {{q}^{2}}=\dfrac{144\times 2500}{9\times {{10}^{9}}}$
$\Rightarrow q=0.63245\times {{10}^{-2}}C$
$\therefore q=6324.5\mu C$
Therefore, we found the magnitude of the charge in microcoulombs to be$q=6324.5\mu C$.
Note:
You may have noticed the proportionality constant that we introduced in the coulomb’s law. This constant is known to have a value given by,
$k=\dfrac{1}{4\pi {{\varepsilon }_{0}}}=9\times {{10}^{9}}N{{C}^{-2}}{{m}^{2}}$
Though there is no mention of signs in the solution, it does have significance. Taking the product will cancel the sign out when they are like charges.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)