The weights of two elements which combines with one another are in the ratio of their:
a) Atomic weight
b) Molecular weight
c) Equivalent weight
d) None of the above
Answer
279.3k+ views
Hint: The law of multiple proportions comes to play in this question. The law of multiple proportions states that when two elements are able to combine with each to form more than one compound, the weights of the element that combine with the fixed weight of the other element are in the ratio of small whole numbers.
Complete answer:
To find the ratio of the weights of the elements, atomic weight of each element is to be determined.
Let us take an example involving carbon and oxygen. Two known forms in which carbon and oxygen combine are carbon monoxide $\left( {CO} \right)$ and carbon dioxide $\left( {C{O_2}} \right).$ Taking oxygen to have the fixed weight in both compounds, in carbon dioxide, for $32g$ of oxygen present there is $12g$ of carbon. By dividing $32g$ by $12g$ , the mass ratio of oxygen to carbon is $2.66$ to $1$ , while in carbon monoxide, for $16g$ of oxygen present there is $12g$ of carbon and the mass ratio is $1.33$ to $1.$ So, the ratio of oxygen in the two compounds is $1:2$ , which is a small whole number ratio.
Therefore, the weights of two elements which combine with one another are in the ratio of their a) Atomic weight.
Note:
The law of multiple proportions is a law of stoichiometry. It can only be applied to compounds containing the same elements. It is an extension of the law of definite proportion (also called Proust’s law), which states that a given chemical compound always contains its component elements in fixed ratio.
Complete answer:
To find the ratio of the weights of the elements, atomic weight of each element is to be determined.
Let us take an example involving carbon and oxygen. Two known forms in which carbon and oxygen combine are carbon monoxide $\left( {CO} \right)$ and carbon dioxide $\left( {C{O_2}} \right).$ Taking oxygen to have the fixed weight in both compounds, in carbon dioxide, for $32g$ of oxygen present there is $12g$ of carbon. By dividing $32g$ by $12g$ , the mass ratio of oxygen to carbon is $2.66$ to $1$ , while in carbon monoxide, for $16g$ of oxygen present there is $12g$ of carbon and the mass ratio is $1.33$ to $1.$ So, the ratio of oxygen in the two compounds is $1:2$ , which is a small whole number ratio.
Therefore, the weights of two elements which combine with one another are in the ratio of their a) Atomic weight.
Note:
The law of multiple proportions is a law of stoichiometry. It can only be applied to compounds containing the same elements. It is an extension of the law of definite proportion (also called Proust’s law), which states that a given chemical compound always contains its component elements in fixed ratio.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Which of the following would not be a valid reason class 11 biology CBSE

Why should electric field lines never cross each other class 12 physics CBSE

An electrostatic field line is a continuous curve That class 12 physics CBSE

What is meant by monosporic development of female class 11 biology CBSE

Draw labelled diagram of the following i Gram seed class 11 biology CBSE

Trending doubts
What is 1 divided by 0 class 8 maths CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

What is the past tense of read class 10 english CBSE

What is pollution? How many types of pollution? Define it

Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE

Change the following sentences into negative and interrogative class 10 english CBSE

How many crores make 10 million class 7 maths CBSE

Give 10 examples for herbs , shrubs , climbers , creepers

How fast is 60 miles per hour in kilometres per ho class 10 maths CBSE
