Answer
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Hint:
Gas constant is denoted by a symbol “R”. In ideal gas, law PV=nRT , R is the gas constant. It is a proportionality constant that relates the energy scale to the temperature scale for a mole of particles at a given temperature.
Complete step by step answer:
In the equation of state of an ideal gas PV=nRT, the value of universal gas constant would depend only on the units of measurement.
This ideal gas law was discovered in 1834.
The value of R depends on the units involved, but is usually stated with S.I. units
i.e. \[R = 8.314{\text{ }}Jmo{l^{ - 1}}{k^{ - 1}}\]
It is independent of the nature of the gas, the pressure of the gas and the temperature of the gas.
For example,
\[R = 8.314{\text{ }}Jmo{l^{ - 1}}{k^{ - 1}}\]
\[\begin{array}{*{20}{l}}
{R = 1.99calmo{l^{ - 1}}{k^{ - 1}}} \\
{R = 0.08206{\text{ }}Latmmo{l^{ - 1}}{K^{ - 1}}}
\end{array}\]
The value of gas constant per degree per mol is approximately 2 cal.
Hence, option B is correct.
Note:
Gas constant is a physical constant that is featured in many fundamental equations in the physical sciences, such as the ideal gas law, the Arrhenius equation, and the Nernst equation. It is equivalent to the Boltzmann constant, but expressed in units of energy per temperature increment per mole, i.e. the pressure volume product, rather than energy per temperature increment per particle.
Gas constant is denoted by a symbol “R”. In ideal gas, law PV=nRT , R is the gas constant. It is a proportionality constant that relates the energy scale to the temperature scale for a mole of particles at a given temperature.
Complete step by step answer:
In the equation of state of an ideal gas PV=nRT, the value of universal gas constant would depend only on the units of measurement.
This ideal gas law was discovered in 1834.
The value of R depends on the units involved, but is usually stated with S.I. units
i.e. \[R = 8.314{\text{ }}Jmo{l^{ - 1}}{k^{ - 1}}\]
It is independent of the nature of the gas, the pressure of the gas and the temperature of the gas.
For example,
\[R = 8.314{\text{ }}Jmo{l^{ - 1}}{k^{ - 1}}\]
\[\begin{array}{*{20}{l}}
{R = 1.99calmo{l^{ - 1}}{k^{ - 1}}} \\
{R = 0.08206{\text{ }}Latmmo{l^{ - 1}}{K^{ - 1}}}
\end{array}\]
The value of gas constant per degree per mol is approximately 2 cal.
Hence, option B is correct.
Note:
Gas constant is a physical constant that is featured in many fundamental equations in the physical sciences, such as the ideal gas law, the Arrhenius equation, and the Nernst equation. It is equivalent to the Boltzmann constant, but expressed in units of energy per temperature increment per mole, i.e. the pressure volume product, rather than energy per temperature increment per particle.
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