Question

# The value of compression of two gases, the rate of diffusion through a fine hole is given by$A.\,\,\,\,\dfrac{{r1}}{{r2\;}} = \dfrac{{P1}}{{P2}}\sqrt {\dfrac{{M1}}{{M2}}} \\B.\,\,\,\dfrac{{r1}}{{r2}} = \dfrac{{P1}}{{P2}}\sqrt {\dfrac{{M2}}{{M1}}} \\C.\,\,\,\dfrac{{r1}}{{r2}} = \sqrt {\dfrac{{P1}}{{P2}}} \dfrac{{M1}}{{M2}} \\D.\,\,\,\dfrac{{r1}}{{r2}} = \sqrt {\dfrac{{P1}}{{P2}}} \dfrac{{M2}}{{M1}} \\$

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Hint:
The rate of diffusion of a gas is inversely proportional to the square root of its molar mass. Gas with the lowest molar mass will have the highest rate of diffusion.

$\dfrac{{r1}}{{r2}} = \dfrac{{P1}}{{P2}}\sqrt {\dfrac{{M2}}{{M1}}}$