Answer
424.2k+ views
Hint: Try to figure out hybridization based on the number of neighboring atoms around boron atoms. Diborane consists of special bonds to satisfy the octet configuration of boron atoms.
Complete step by step answer:
- We know that diborane consists of 2 boron atoms and 6 hydrogen atoms. Out of these 6 hydrogen atoms 4 hydrogen atoms are attached to only one boron atom remaining two hydrogen atoms are attached to both borons through a special type of bond.
-Boron has 3 electrons in valence shell; it cannot complete octet directly through covalent bonds. In the excited state of boron, it has 3 unpaired electrons with 4 orbitals which can involve in bonding. In diborane 2 hydrogen atoms in between two boron atoms are connected to both atoms through a special 3 centered 2 electron bond. In 3 centered 2 electron bonds, 2 electrons are shared in between 3 centers; those are 2 boron atoms and 1 hydrogen atom to satisfy the octet of boron. This type of bond is also considered as regular while calculating hybridization. Since each boron atom has 4 bonds so hybridization will $sp^{ 3 }$ – hybridization.
Therefore, option B is correct.
Note:
has only 3 electrons in the outer shell and can form only 3 hybridized orbitals. So both boron atoms are connected whether it is through direct or indirect bonding.
Complete step by step answer:
- We know that diborane consists of 2 boron atoms and 6 hydrogen atoms. Out of these 6 hydrogen atoms 4 hydrogen atoms are attached to only one boron atom remaining two hydrogen atoms are attached to both borons through a special type of bond.
-Boron has 3 electrons in valence shell; it cannot complete octet directly through covalent bonds. In the excited state of boron, it has 3 unpaired electrons with 4 orbitals which can involve in bonding. In diborane 2 hydrogen atoms in between two boron atoms are connected to both atoms through a special 3 centered 2 electron bond. In 3 centered 2 electron bonds, 2 electrons are shared in between 3 centers; those are 2 boron atoms and 1 hydrogen atom to satisfy the octet of boron. This type of bond is also considered as regular while calculating hybridization. Since each boron atom has 4 bonds so hybridization will $sp^{ 3 }$ – hybridization.
![seo images](https://www.vedantu.com/question-sets/329edcda-8be7-4e66-8834-5baeccc982084780890870188577257.png)
Therefore, option B is correct.
Note:
has only 3 electrons in the outer shell and can form only 3 hybridized orbitals. So both boron atoms are connected whether it is through direct or indirect bonding.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)