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# The sub energy level having minimum energy is A. 3dB. 5pC. 4sD. 4p

Last updated date: 20th Jun 2024
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Hint: The electrons in an atom revolves around the nucleus in a particular shell i.e. K, L, M, N……….The first shell can accommodate $2$ electrons. Second and third shells contain $8,8$electrons respectively. Further, the fourth and fifth shells contain $18,18$ electrons and so on. After then the shells are subdivided into the atomic orbitals i.e. s, p, d, f. s can accommodate two electrons, p contains 6 and d & f contains $10,14$ electrons respectively.

The atomic orbitals of an atom fill with electrons according to Afbau principle.
Afbau principle: - According to this principle, the electrons are filled into atomic orbitals in the increasing order of their energy. Increasing order of atomic orbital is written as 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p and so on.
The first atomic orbital having minimum energy & then further atomic orbital slightly higher energy than first atomic orbital and so on.
According to Afbau principle the solution of the given statement is $4s$ i.e. option ‘C’ is correct.

So, the correct answer is “Option C”.

To solve such a kind of statement, the knowledge of atomic orbital and their types must be known. One should know the Afbau principle & increasing order of energy levels. An orbital contains maximum two electrons having opposite spins according to Pauli Exclusion principle. There are maximum $\left( \text{2l}+\text{1} \right)$orbitals for a given subshell as the value of l for ‘s’ subshell is zero so it contains 1 orbital only i.e. maximum two electrons.