The speed of a transverse wave on a stretched string is:
A). directly proportional to the tension in the string.
B). directly proportional to the square root of the tension.
C). inversely proportional to tension.
D). inversely proportional to the square root of the tension.
Answer
622.2k+ views
Hint: In a transverse wave, the particles of the medium vibrate along the direction perpendicular to the motion of the wave. The speed of the wave on the string is dependent on the tension in the string and mass per unit length of the given string. The exact dependence can be easily found using dimensional analysis.
Formula used: speed of the wave
$\sqrt{\dfrac{T}{\mu }}$
Complete step-by-step solution:
The speed of the transverse wave on a stretched string will be dependent on the tension in the string and on the mass per unit length of the string. We will use dimensional analysis to find the exact dependence and will get the answer to the given question. Dimensions of tension will be the same as Force and dimensions of μ i.e. mass per unit length will be of mass divided by length.
$\begin{align}
& v\propto {{T}^{a}}{{\mu }^{b}} \\
& [L{{T}^{-1}}]={{[ML{{T}^{-2}}]}^{a}}{{[M{{L}^{-1}}]}^{b}}=[{{M}^{a+b}}{{L}^{a-b}}{{T}^{-2a}}] \\
\end{align}$
We get the following relations from the expression above
$a+b = 0$
$a-b = 1$
$-2a = -1$
When we solve them we get a = $\dfrac{1}{2}$ and b = \[-\dfrac{1}{2}\]
So, it can be seen that v is proportional to the square root of the tension. Hence, the correct option is B, i.e. directly proportional to the square root of the tension.
Note: We can also find the exact relation using other rigorous mathematical methods, but that will be very tedious and time-consuming so it is advised to stick to dimensional analysis as it is easy and also gets us the desired result and the correct solution with minimal effort.
Formula used: speed of the wave
$\sqrt{\dfrac{T}{\mu }}$
Complete step-by-step solution:
The speed of the transverse wave on a stretched string will be dependent on the tension in the string and on the mass per unit length of the string. We will use dimensional analysis to find the exact dependence and will get the answer to the given question. Dimensions of tension will be the same as Force and dimensions of μ i.e. mass per unit length will be of mass divided by length.
$\begin{align}
& v\propto {{T}^{a}}{{\mu }^{b}} \\
& [L{{T}^{-1}}]={{[ML{{T}^{-2}}]}^{a}}{{[M{{L}^{-1}}]}^{b}}=[{{M}^{a+b}}{{L}^{a-b}}{{T}^{-2a}}] \\
\end{align}$
We get the following relations from the expression above
$a+b = 0$
$a-b = 1$
$-2a = -1$
When we solve them we get a = $\dfrac{1}{2}$ and b = \[-\dfrac{1}{2}\]
So, it can be seen that v is proportional to the square root of the tension. Hence, the correct option is B, i.e. directly proportional to the square root of the tension.
Note: We can also find the exact relation using other rigorous mathematical methods, but that will be very tedious and time-consuming so it is advised to stick to dimensional analysis as it is easy and also gets us the desired result and the correct solution with minimal effort.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

How many of the following diseases can be studied with class 11 biology CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

Which of the following enzymes is used for carboxylation class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

