
The specific heat of water is 4.184 J/g times Celsius degree. How much heat is required to raise the temperature of 5.0 g of water by 3.0 degree Celsius?
Answer
556.8k+ views
Hint:In order to answer a question, we must know a specific heat capacity is. Specific heat capacity is the amount of heat which is added to a substance of unit mass, in order to raise the temperature by one degree Celsius.
Complete answer:
Let us first understand about the heat capacity. It is the amount of heat which is required to raise the temperature of the substance by one degree Celsius. Now let us see what a specific capacity is. Specific heat capacity is the amount of heat which is added to a substance of unit mass, in order to raise the temperature by one degree Celsius. The quantity of specific heat is usually measured in Joules. We know that specific heat of water is around 4.184 \[J/{g^\circ }C\].
Now let us move onto the problem.
Write the equation of the specific heat capacity, i.e.,
\[Q = mc\Delta T\]……. (1)
Where Q is the energy in Joules
m is the mass in Grams
c is the specific heat capacity
\[\Delta T\]is the change in temperature.
Therefore, from the equation, we get
\[Q = (5 \times 4.184 \times 3) = 62.76J\].
62.76J of heat is required to raise the temperature.
Note:
Let us see some of the applications
- Cooling vessels are made of metals which have low specific capacity.
- Land and sea breezes make use of the principle of specific heat capacity.
- It is also used in the car radiators
Complete answer:
Let us first understand about the heat capacity. It is the amount of heat which is required to raise the temperature of the substance by one degree Celsius. Now let us see what a specific capacity is. Specific heat capacity is the amount of heat which is added to a substance of unit mass, in order to raise the temperature by one degree Celsius. The quantity of specific heat is usually measured in Joules. We know that specific heat of water is around 4.184 \[J/{g^\circ }C\].
Now let us move onto the problem.
Write the equation of the specific heat capacity, i.e.,
\[Q = mc\Delta T\]……. (1)
Where Q is the energy in Joules
m is the mass in Grams
c is the specific heat capacity
\[\Delta T\]is the change in temperature.
Therefore, from the equation, we get
\[Q = (5 \times 4.184 \times 3) = 62.76J\].
62.76J of heat is required to raise the temperature.
Note:
Let us see some of the applications
- Cooling vessels are made of metals which have low specific capacity.
- Land and sea breezes make use of the principle of specific heat capacity.
- It is also used in the car radiators
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

