Answer
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Hint: The carboxylic acid consists of the COOH group. It has an active hydrogen atom. The metal reacts with the acid to release the active hydrogen and form the salt. The two hydrogen atoms combine to give hydrogen gas.
Complete Solution :
We all know that the acid consists of an active hydrogen atom. The metal reacts with the acid to release the active hydrogen and form the salt. The two hydrogen atoms combine to give hydrogen gas. The reaction of metal with an acid can be written as -
$Acid + Metal \to Salt + {H_2}(g)( \uparrow )$
So, the correct answer is “Option C”.
Additional Information:
Normally dilute metals react with acids to form salt and hydrogen gas. To predict which metal would react with which acid, it can be known from the reactivity series of metals with dilute acids. To confirm whether a reaction has taken place between a metal and an acid, the best way is to do a hydrogen pop test. Because if the reaction has occurred, the hydrogen gas would have evolved.
Note: It must be noted that the salt produced would depend upon the metal used and the acid used. Suppose we say, the ethanoic acid combines with sodium. The reaction would be written as -
$C{H_3}COOH + Na \to C{H_3}COONa + {H_2}$
It will give sodium salt of ethanoic acid. If any other acid or metal is used, the product would be different.
Complete Solution :
We all know that the acid consists of an active hydrogen atom. The metal reacts with the acid to release the active hydrogen and form the salt. The two hydrogen atoms combine to give hydrogen gas. The reaction of metal with an acid can be written as -
$Acid + Metal \to Salt + {H_2}(g)( \uparrow )$
So, the correct answer is “Option C”.
Additional Information:
Normally dilute metals react with acids to form salt and hydrogen gas. To predict which metal would react with which acid, it can be known from the reactivity series of metals with dilute acids. To confirm whether a reaction has taken place between a metal and an acid, the best way is to do a hydrogen pop test. Because if the reaction has occurred, the hydrogen gas would have evolved.
Note: It must be noted that the salt produced would depend upon the metal used and the acid used. Suppose we say, the ethanoic acid combines with sodium. The reaction would be written as -
$C{H_3}COOH + Na \to C{H_3}COONa + {H_2}$
It will give sodium salt of ethanoic acid. If any other acid or metal is used, the product would be different.
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