Question

The reaction between ${O_3}$ and KI solution gives which of the following?
A) ${K_2}O$
B) ${I_2}$
C) $HI$
D) $HI{O_3}$

Answer 1

Hint:Ozone or ${O_3}$ is an oxidizing agent. Any compound that accepts electrons or adds oxygen atoms to another compound or molecule is known as an oxidizing agent. Hence when ozone reacts with potassium iodide, it reduces itself and oxidizes potassium iodide.

Complete step-by-step answer:Given to us are two compounds Ozone and potassium iodide. The compound ozone is an oxidizing agent. When ozone reacts with potassium iodide, it reduces itself and oxidizes potassium iodide.The compound potassium iodide is oxidized to form iodide molecules. Ozone reduces itself and becomes an oxygen molecule which will be evaporated as gas. We can also understand that potassium hydroxide is also produced as a byproduct. We can write an equation for this reaction as follows.
${O_3} + {H_2}O + KI \to {I_2} + KOH + {{\rm O}_2}$
Now, let us balance this equation.
${O_3} + {H_2}O + 2KI \to {I_2} + 2KOH + {O_2}$
Hence, the products formed during the reaction between ozone and potassium iodide solution are iodine molecule, potassium hydride and oxygen molecule.

Additional information: An oxidizing agent can oxidize a compound by adding oxygen atoms to it or by removing hydrogen atoms from it. Similarly a reducing agent can reduce a compound by adding hydrogen atoms to it or by removing oxygen atoms from it.

Therefore the correct answer is option B).

Note: It is to be noted that a equation for a reaction should always be balanced in order to understand the stoichiometric values of the reactants and products. Ozone oxidizes potassium iodide by giving an oxygen atom and reducing itself to a dioxygen molecule.