
The radii of the ends of a bucket \[30cm\] high is \[21cm\] and \[7cm\]. Find its capacity in litres and the amount of sheet required to make this bucket.
A. \[20.02{\text{ liters ; 3067}}c{m^2}\]
B. \[20.02{\text{ liters ; 3867}}c{m^2}\]
C. \[25.02{\text{ liters ; 3067}}c{m^2}\]
D. \[10.02{\text{ liters ; 3067}}c{m^2}\]
Answer
620.1k+ views
Hint: Here the volume of the bucket is equal to the capacity of the bucket in litres. We can find the amount of sheet required to make this bucket by calculating the total surface area of the bucket.
Complete step-by-step answer:
Given,
Height of the bucket \[h = 30cm\]
Radius of upper end of the bucket \[R = 21cm\]
Radius of lower end of the bucket \[r = 7cm\]
We know that volume of the bucket = \[\dfrac{1}{3}\pi h\left( {{R^2} + {r^2} + Rr} \right)c{m^3}\]
\[
= \dfrac{1}{3}\pi (30)\left( {{{\left( {21} \right)}^2} + {{\left( 7 \right)}^2} + \left( {21} \right)\left( 7 \right)} \right) \\
= \dfrac{1}{3}\pi \left( {30} \right)\left( {441 + 49 + 147} \right) \\
= \dfrac{1}{3}\pi \left( {30} \right)\left( {637} \right) \\
= \dfrac{1}{3} \times \dfrac{{22}}{7}\left( {19110} \right) \\
= \dfrac{{420420}}{{21}} = 20020c{m^3} \\
\]
Since, \[1c{m^3} = \dfrac{1}{{1000}}{\text{ litres}}\]
The capacity of the bucket is \[\dfrac{{20020}}{{1000}}{\text{ litres }} = {\text{ 20}}{\text{.02 litres}}\]
We know that slant height of the bucket \[l = \sqrt {{h^2} + {{\left( {R - r} \right)}^2}} \]
\[
l = \sqrt {{{30}^2} + {{\left( {21 - 7} \right)}^2}} \\
l = \sqrt {900 + {{\left( {14} \right)}^2}} \\
l = \sqrt {900 + 196} \\
l = \sqrt {1096} \\
\therefore l = 33.10cm \\
\]
Total area of the metal sheet required to make the bucket = \[\pi l\left( {R + r} \right) + \pi {r^2}\]
\[
= \pi \times 33.10\left( {21 + 7} \right) + \pi \times {7^2} \\
= \pi \times 33.10\left( {28} \right) + \pi \times 49 \\
= \pi \times 926.8 + \pi \times 49 \\
= \pi \left( {926.8 + 49} \right) \\
= \dfrac{{22}}{7} \times 975.8 \\
= \dfrac{{21467.6}}{7} \\
= 3066.8 \approx 3067c{m^2} \\
\]
Therefore, the amount of sheet required to make the bucket is \[{\text{3067}}c{m^2}\].
Thus, the capacity of the bucket is \[20.02{\text{ litres}}\] and the amount of sheet required to make the bucket is \[{\text{3067}}c{m^2}\].
So, the correct option is A. \[20.02{\text{ liters ; 3067}}c{m^2}\].
Note: The height given in the problem is the altitude of the bucket. To find the surface area we have to consider the slant height which is given by \[l = \sqrt {{h^2} + {{\left( {R - r} \right)}^2}} \]. We have converted the volume of the bucket in to capacity of the bucket in litres by using the conversion \[1c{m^3} = \dfrac{1}{{1000}}{\text{ litres}}\].
Complete step-by-step answer:
Given,
Height of the bucket \[h = 30cm\]
Radius of upper end of the bucket \[R = 21cm\]
Radius of lower end of the bucket \[r = 7cm\]
We know that volume of the bucket = \[\dfrac{1}{3}\pi h\left( {{R^2} + {r^2} + Rr} \right)c{m^3}\]
\[
= \dfrac{1}{3}\pi (30)\left( {{{\left( {21} \right)}^2} + {{\left( 7 \right)}^2} + \left( {21} \right)\left( 7 \right)} \right) \\
= \dfrac{1}{3}\pi \left( {30} \right)\left( {441 + 49 + 147} \right) \\
= \dfrac{1}{3}\pi \left( {30} \right)\left( {637} \right) \\
= \dfrac{1}{3} \times \dfrac{{22}}{7}\left( {19110} \right) \\
= \dfrac{{420420}}{{21}} = 20020c{m^3} \\
\]
Since, \[1c{m^3} = \dfrac{1}{{1000}}{\text{ litres}}\]
The capacity of the bucket is \[\dfrac{{20020}}{{1000}}{\text{ litres }} = {\text{ 20}}{\text{.02 litres}}\]
We know that slant height of the bucket \[l = \sqrt {{h^2} + {{\left( {R - r} \right)}^2}} \]
\[
l = \sqrt {{{30}^2} + {{\left( {21 - 7} \right)}^2}} \\
l = \sqrt {900 + {{\left( {14} \right)}^2}} \\
l = \sqrt {900 + 196} \\
l = \sqrt {1096} \\
\therefore l = 33.10cm \\
\]
Total area of the metal sheet required to make the bucket = \[\pi l\left( {R + r} \right) + \pi {r^2}\]
\[
= \pi \times 33.10\left( {21 + 7} \right) + \pi \times {7^2} \\
= \pi \times 33.10\left( {28} \right) + \pi \times 49 \\
= \pi \times 926.8 + \pi \times 49 \\
= \pi \left( {926.8 + 49} \right) \\
= \dfrac{{22}}{7} \times 975.8 \\
= \dfrac{{21467.6}}{7} \\
= 3066.8 \approx 3067c{m^2} \\
\]
Therefore, the amount of sheet required to make the bucket is \[{\text{3067}}c{m^2}\].
Thus, the capacity of the bucket is \[20.02{\text{ litres}}\] and the amount of sheet required to make the bucket is \[{\text{3067}}c{m^2}\].
So, the correct option is A. \[20.02{\text{ liters ; 3067}}c{m^2}\].
Note: The height given in the problem is the altitude of the bucket. To find the surface area we have to consider the slant height which is given by \[l = \sqrt {{h^2} + {{\left( {R - r} \right)}^2}} \]. We have converted the volume of the bucket in to capacity of the bucket in litres by using the conversion \[1c{m^3} = \dfrac{1}{{1000}}{\text{ litres}}\].
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

