
The price of a table is Rs.400 more than that of a chair. If 6 tables and 6 chairs together cost Rs.4800, by what percent is the price of the chair less than that of the table?
A.\[33\dfrac{1}{3}\% \]
B. \[50\% \]
C. \[66\dfrac{2}{3}\% \]
D. None of these
Answer
458.1k+ views
Hint: We assume the price of chair as a variable and use the relation given in the question to write the price of table in terms of price of chair. Form an equation for number of items multiplied with the initial amount of item and write sum from tables and chair and equate with given amount. Calculate the value of the variable. Use a method of percentage to calculate percentage of price of chair.
* Percentage of a particular item with respect to another item is given by dividing the value of that item by the value of another item and multiplying by 100.
Complete answer:
Let us assume price of chair as ‘x’
Then we are given that the price of a table is Rs.400 more than that of a chair
So, price of table \[ = x + 400\]
Now we are given that there are 6 tables and 6 chairs, they together have price Rs.4800
We form an equation where we add the product of price of a chair with 6 chairs and price of a table with 6 tables and equate that sum to Rs.4800
\[ \Rightarrow x \times 6 + (x + 400) \times 6 = 4800\]
Since we can write \[4800 = 6 \times 800\]
\[ \Rightarrow x \times 6 + (x + 400) \times 6 = 6 \times 800\]
Cancel same factors i.e. 6 from both sides of the equation
\[ \Rightarrow x + x + 400 = 800\]
Shift all constant values to RHS of the equation
\[ \Rightarrow 2x = 800 - 400\]
\[ \Rightarrow 2x = 400\]
Cancel same factors i.e. 2 from both sides of the equation
\[ \Rightarrow x = 200\]
So, the price of 1 chair is Rs.200
Also, we know price of a table \[ = 200 + 400\] i.e. 600
So, the price of 1 table is Rs.600
Now we have to calculate by what percentage is the price of the chair less than that of the table.
So, we have to calculate the percentage of price by which the chair is less than the table.
\[ \Rightarrow \]Percentage \[ = \left( {\dfrac{{200}}{{600}} \times 100} \right)\% \]
Cancel same factors from numerator and denominator
\[ \Rightarrow \]Percentage \[ = \left( {\dfrac{1}{3} \times 100} \right)\% \]
Convert division of 100 by 3 into mixed fraction where 33 is quotient, 3 is divisor and 1 is the remainder
\[ \Rightarrow \]Percentage \[ = 33\dfrac{1}{3}\% \]
\[\therefore \]Correct option is A.
Note:
Many students are likely to get confused when calculating the percentage as they tend to take the sum of prices of both table and chairs in the denominator, keep in mind we take that term in denominator to whose comparison we are making, in this case we want to see what percent is price of chair less than price of table so price of table will be in denominator.
* Percentage of a particular item with respect to another item is given by dividing the value of that item by the value of another item and multiplying by 100.
Complete answer:
Let us assume price of chair as ‘x’
Then we are given that the price of a table is Rs.400 more than that of a chair
So, price of table \[ = x + 400\]
Now we are given that there are 6 tables and 6 chairs, they together have price Rs.4800
We form an equation where we add the product of price of a chair with 6 chairs and price of a table with 6 tables and equate that sum to Rs.4800
\[ \Rightarrow x \times 6 + (x + 400) \times 6 = 4800\]
Since we can write \[4800 = 6 \times 800\]
\[ \Rightarrow x \times 6 + (x + 400) \times 6 = 6 \times 800\]
Cancel same factors i.e. 6 from both sides of the equation
\[ \Rightarrow x + x + 400 = 800\]
Shift all constant values to RHS of the equation
\[ \Rightarrow 2x = 800 - 400\]
\[ \Rightarrow 2x = 400\]
Cancel same factors i.e. 2 from both sides of the equation
\[ \Rightarrow x = 200\]
So, the price of 1 chair is Rs.200
Also, we know price of a table \[ = 200 + 400\] i.e. 600
So, the price of 1 table is Rs.600
Now we have to calculate by what percentage is the price of the chair less than that of the table.
So, we have to calculate the percentage of price by which the chair is less than the table.
\[ \Rightarrow \]Percentage \[ = \left( {\dfrac{{200}}{{600}} \times 100} \right)\% \]
Cancel same factors from numerator and denominator
\[ \Rightarrow \]Percentage \[ = \left( {\dfrac{1}{3} \times 100} \right)\% \]
Convert division of 100 by 3 into mixed fraction where 33 is quotient, 3 is divisor and 1 is the remainder
\[ \Rightarrow \]Percentage \[ = 33\dfrac{1}{3}\% \]
\[\therefore \]Correct option is A.
Note:
Many students are likely to get confused when calculating the percentage as they tend to take the sum of prices of both table and chairs in the denominator, keep in mind we take that term in denominator to whose comparison we are making, in this case we want to see what percent is price of chair less than price of table so price of table will be in denominator.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

The correct geometry and hybridization for XeF4 are class 11 chemistry CBSE

Water softening by Clarks process uses ACalcium bicarbonate class 11 chemistry CBSE

With reference to graphite and diamond which of the class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

State and prove Bernoullis theorem class 11 physics CBSE

What organs are located on the left side of your body class 11 biology CBSE

How many valence electrons does nitrogen have class 11 chemistry CBSE
