
The potential energy of spring is given by $U=\dfrac{1}{2}k{{x}^{2}}$, where $x$ is extension spring. Find the force associated with this potential energy in y-direction.
Answer
505.5k+ views
Hint:The relation between force and potential energy is $F=-\dfrac{dU}{dr}$.When we find force along x-direction then we differentiate the potential energy with respect to $x$ and when we find the force along $y$-direction then we differentiate the potential energy with respect to $y$.
Complete step by step answer:
Spring force is a type of conservative force
$F=-\dfrac{dU}{dr}$
where, $U$is potential energy and $r$ is position vector in the direction of conservative force $F$ is conservative force.
Work done by the conservative force is equal to negative of change in potential energy
$w=-\Delta U$
Given, $U=\dfrac{1}{2}k{{x}^{2}}$
Put in the formula of force. When we calculate the force associated with this potential energy in x-direction then we take the position vector as $x$. It means that we differentiate the potential energy with respect to $x$.
$F=-\dfrac{dU}{dx}$
After putting the value of $U$in above equation then we get
$F=-\dfrac{d}{dx}(\dfrac{1}{2}k{{x}^{2}})$
$\Rightarrow F=-\dfrac{1}{2}k\dfrac{d}{dx}({{x}^{2}})$
The simple differentiation formula in the above equation is $\dfrac{d}{dx}({{x}^{n}})=n{{x}^{n-1}}$.
$F=-\dfrac{1}{2}k\times 2x$
$\Rightarrow F=-kx$
Hence, the force along x-direction.
When we calculate the force associated with this potential energy in y-direction then we take the position vector as y it means that we differentiate the potential energy with respect to y.
$F=-\dfrac{dU}{dy}$
After putting the value of $U$in above equation then we get
$F=-\dfrac{d}{dy}(\dfrac{1}{2}k{{x}^{2}})$
$\Rightarrow F=-\dfrac{1}{2}k\dfrac{d}{dy}({{x}^{2}})$
When we differentiate ${{x}^{2}}$with respect to y then it became zero
$\therefore F=0$
Hence, the force along y-direction is zero.
Note:The negative sign shows the spring force is a type of restoring force. The elastic potential energy of an undeformed spring is taken to be zero. Spring force is a conservative force and the conservative force does not dissipate the energy of the system into heat.
Complete step by step answer:
Spring force is a type of conservative force
$F=-\dfrac{dU}{dr}$
where, $U$is potential energy and $r$ is position vector in the direction of conservative force $F$ is conservative force.
Work done by the conservative force is equal to negative of change in potential energy
$w=-\Delta U$
Given, $U=\dfrac{1}{2}k{{x}^{2}}$
Put in the formula of force. When we calculate the force associated with this potential energy in x-direction then we take the position vector as $x$. It means that we differentiate the potential energy with respect to $x$.
$F=-\dfrac{dU}{dx}$
After putting the value of $U$in above equation then we get
$F=-\dfrac{d}{dx}(\dfrac{1}{2}k{{x}^{2}})$
$\Rightarrow F=-\dfrac{1}{2}k\dfrac{d}{dx}({{x}^{2}})$
The simple differentiation formula in the above equation is $\dfrac{d}{dx}({{x}^{n}})=n{{x}^{n-1}}$.
$F=-\dfrac{1}{2}k\times 2x$
$\Rightarrow F=-kx$
Hence, the force along x-direction.
When we calculate the force associated with this potential energy in y-direction then we take the position vector as y it means that we differentiate the potential energy with respect to y.
$F=-\dfrac{dU}{dy}$
After putting the value of $U$in above equation then we get
$F=-\dfrac{d}{dy}(\dfrac{1}{2}k{{x}^{2}})$
$\Rightarrow F=-\dfrac{1}{2}k\dfrac{d}{dy}({{x}^{2}})$
When we differentiate ${{x}^{2}}$with respect to y then it became zero
$\therefore F=0$
Hence, the force along y-direction is zero.
Note:The negative sign shows the spring force is a type of restoring force. The elastic potential energy of an undeformed spring is taken to be zero. Spring force is a conservative force and the conservative force does not dissipate the energy of the system into heat.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

