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**Hint:**The given question can be solved by considering, the volume of one mole of any gas is known as molar volume is equal to $22.4L$ at standard temperature and pressure. Molar volume allows conversion to be made between volume and moles of any gases at standard temperature.

**Complete answer:**

We know any type of gas occupies approximately $22.4litres$ of space at standard temperature pressure, we also know $1mole$ of contain Avogadro’s number of molecules.

So, we can say $1mole$ of ammonia $(N{H_3})$ occupies $22.4litres$ and it has Avogadro’s molecules ($6.023 \times {10^{23}}$ molecules).

Therefore, $1litre$ contain $\dfrac{1}{{22.4}}$ moles and $10litres$ contain $\dfrac{{10}}{{22.4}}$ moles of ammonia.

Now, the number of molecules in $\dfrac{{10}}{{22.4}}$ moles of ammonia is $\dfrac{{10}}{{22.4}} \times 6.022 \times {10^{23}}$ molecules, but our aim to calculate the number of atom. In ammonia molecules there are four atoms. So multiply the number of molecules by four.

Number of atom is $10litres$ of ammonia $ = 4 \times \dfrac{{10}}{{22.4}} \times 6.022 \times {10^{23}}atoms$

On solving the above equation, we get

$ = 1.786 \times 6.022 \times {10^{23}}atoms$

**Hence $10litres$ of ammonia contain $1.786 \times 6.022 \times {10^{23}}atoms$ . so the correct option is \[D.\]**

**Additional information:**Avogadro’s number: Avogadro’s number of atom or molecules in mole of substance is equal to $6.023 \times {10^{23}}$. we can calculate the Avogadro’s number by dividing the charge of one mole of electron by the charge on a single electron we get a value of Avogadro’s number of $6.023 \times {10^{23}}$ particles per mole. The unit of avogadro’s number is $mo{l^{ - 1}}$ .

Ammonia: Ammonia is a colourless gas with a distinct odour composed of nitrogen and oxygen. The chemical formula of ammonia is $N{H_3}$ . Ammonia is an important component of the metabolic process.

**Note:**It is to be noted that one mole of any gas contains $22.4L$ volume at standard temperature and pressure of gas. We can calculate the volume at $STP$ by using the ideal gas equation. The ideal gas reaction is $PV = nRT$ .

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