Answer

Verified

425.1k+ views

**Hint:**

Molarity and Molality are two different concepts, where molarity is related to the volume of the solution and molality is related to mass of the solvent.

**Formula Used:**

Molarity = \[\dfrac{{number{\text{ }}of{\text{ }}moles{\text{ }}of{\text{ }}solute}}{{volume{\text{ }}of{\text{ }}solution{\text{ }}\left( {in{\text{ }}litres} \right)}}\]

Total mass = (molecular mass) (number of moles of substance present)

**Complete step by step answer:**

Molarity of a solution is basically the measure of the amount of solute present in the solution. It can be defined in a mathematical relation as the ratio of the numbers of moles of the solute present in the solution to the volume of the solution. It must be noted that the volume of the solution must be denoted in litres.

Hence, we can write this in the form of an equation as:

Molarity = \[\dfrac{{number{\text{ }}of{\text{ }}moles{\text{ }}of{\text{ }}solute}}{{volume{\text{ }}of{\text{ }}solution{\text{ }}\left( {in{\text{ }}litres} \right)}}\]

In the problem given to us, the data that has been provided is;

Molarity = 0.75M, and the volume of solute = 300ml = 0.3 L

Hence, substituting these values in the above formula we get,

0.75 = \[\dfrac{{number{\text{ }}of{\text{ }}moles{\text{ }}of{\text{ }}solute}}{{0.3}}\]

\[\therefore number{\text{ }}of{\text{ }}moles{\text{ }}of{\text{ }}solute = 0.75 \times 0.3\]= 0.225 moles

Now to calculate the mass of the solute, we can use the following formula:

Total mass = (molecular mass) (number of moles of substance present)

= (58) (0.225)

= 13.05 g

**Hence, Option A is the correct option.**

**Note:**

The volume of the solution must be converted to litres before proceeding with the calculation. Failing to do so would result in an error of the factor of \[{10^3}\]

Recently Updated Pages

How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE

Why Are Noble Gases NonReactive class 11 chemistry CBSE

Let X and Y be the sets of all positive divisors of class 11 maths CBSE

Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE

Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE

Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE

Trending doubts

Establish a relation between electric current and drift class 12 physics CBSE

Guru Purnima speech in English in 100 words class 7 english CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Difference Between Plant Cell and Animal Cell

Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

Copper is not used as potentiometer wire because class 12 physics CBSE

Give 10 examples for herbs , shrubs , climbers , creepers

Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE