
The molar heat capacity of silver is $\dfrac{{25.35J}}{{mo{l^ \circ }C}}$. How much energy would it take to raise the temperature of $10.2g$ of silver by $14.0$ degrees $C$?
Answer
545.7k+ views
Hint:That amount of energy that must be added in the heat form to one mole of substance in order to increase one unit of the temperature is called molar specific heat capacity. Converting the amount of silver into moles will help to bet the answer.
Formula used:
$q = mc\Delta T$
Where, $m$ is the mass, $c$ is the specific heat capacity and $\Delta T$ is the change in the temperature.
Complete step by step answer:
Molar heat capacity is the closely related property of the substances. In which the heat capacity of the sample is divided by the moles of the atom instead of the moles of molecules. That amount of energy that must be added in the heat form to one mole of substance in order to increase one unit of the temperature is called a molar specific heat capacity. It can be calculated as,
$q = mc\Delta T$
We have got the values. The mass is $10.2g$, molar capacity value is $\dfrac{{25.35J}}{{mo{l^ \circ }C}}$. The temperature change is ${14.0^ \circ }C$. Let us convert the amount of silver into moles. The silver has a molar mass $107.8682g/mol$.Divide the values of the mass and the molar mass of the silver.
$\dfrac{{10.2g}}{{107.8682g/mol}}$
Cancel out the common terms gram. We get,
$ \Rightarrow \dfrac{{10.2}}{{107.8682/mol}}$
Divide the terms we get,
$ \Rightarrow 0.0945598425mol$
Keep the number as it is and it can round it off at the end.
The energy required is,
$ \Rightarrow q = 0.0945598425mol.\dfrac{{25.35J}}{{mo{l^ \circ }C}}{.14^ \circ }C$
Cancel out the common terms. The common terms are $mol$ and ${}^ \circ C$. We get,
$ \Rightarrow q = 0.0945598425 \times 25.35 \times 14$
Multiply the above values to get the answer. The answer is
$ \Rightarrow 33.4269043J$
The above value is approximately equal to,
$ \simeq 33.6J$
Therefore, the energy that is required to raise is $33.6J$.
Note:The value of the molar volumes of the solid elements roughly equals constant and therefore the molar heat capacity of the solid is also the same. At the higher end of the heat capacities, the heat capacity will exceed the value of the gas constant.
Formula used:
$q = mc\Delta T$
Where, $m$ is the mass, $c$ is the specific heat capacity and $\Delta T$ is the change in the temperature.
Complete step by step answer:
Molar heat capacity is the closely related property of the substances. In which the heat capacity of the sample is divided by the moles of the atom instead of the moles of molecules. That amount of energy that must be added in the heat form to one mole of substance in order to increase one unit of the temperature is called a molar specific heat capacity. It can be calculated as,
$q = mc\Delta T$
We have got the values. The mass is $10.2g$, molar capacity value is $\dfrac{{25.35J}}{{mo{l^ \circ }C}}$. The temperature change is ${14.0^ \circ }C$. Let us convert the amount of silver into moles. The silver has a molar mass $107.8682g/mol$.Divide the values of the mass and the molar mass of the silver.
$\dfrac{{10.2g}}{{107.8682g/mol}}$
Cancel out the common terms gram. We get,
$ \Rightarrow \dfrac{{10.2}}{{107.8682/mol}}$
Divide the terms we get,
$ \Rightarrow 0.0945598425mol$
Keep the number as it is and it can round it off at the end.
The energy required is,
$ \Rightarrow q = 0.0945598425mol.\dfrac{{25.35J}}{{mo{l^ \circ }C}}{.14^ \circ }C$
Cancel out the common terms. The common terms are $mol$ and ${}^ \circ C$. We get,
$ \Rightarrow q = 0.0945598425 \times 25.35 \times 14$
Multiply the above values to get the answer. The answer is
$ \Rightarrow 33.4269043J$
The above value is approximately equal to,
$ \simeq 33.6J$
Therefore, the energy that is required to raise is $33.6J$.
Note:The value of the molar volumes of the solid elements roughly equals constant and therefore the molar heat capacity of the solid is also the same. At the higher end of the heat capacities, the heat capacity will exceed the value of the gas constant.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

