
The minimum value of ${x^2} - 12x + 40$ and the maximum value of $24x - 8 - 9{x^2}$ is?
Answer
621.3k+ views
Hint-In this question we have to find the minimum and maximum value of the given quadratic equations. Check for the coefficient of highest power term to be positive or negative and apply the respective formula for maximum and minimum value of a quadratic equation.
Complete step-by-step answer:
We have to find the minimum value of ${x^2} - 12x + 40$ and the maximum value of $24x - 8 - 9{x^2}$.
$ \Rightarrow $ Now if we have a quadratic equation of the form ${\text{a}}{{\text{x}}^2} + bx + c = 0$such that $a > 0$ then the minimum value of this quadratic equation is $\dfrac{{4ac - {b^2}}}{{2a}}$at the point x=$\dfrac{b}{{2a}}$ and in this case the maximum value doesn’t exist as the parabola formed is opening upwards and the domain of this equation is R (that is real numbers) thus the max value can go up to infinity.
$ \Rightarrow $ Now if we talk about a quadratic equation of the form ${\text{a}}{{\text{x}}^2} + bx + c = 0$ such that $a < 0$ then the maximum value of this quadratic equation is $\dfrac{{4ac - {b^2}}}{{2a}}$ at point x=$\dfrac{{ - b}}{{2a}}$ and in this case the minimum does not exist as the parabola formed is opening downwards and the domain of this equation is R (that is real numbers) thus the min value can go up to minus infinity.
Now in the equation ${x^2} - 12x + 40$ a=1, b=-12 and c=40
As $a > 0$ because 1>0, hence using the above mentioned concept it does not have a maximum value and the minimum value is given by $\dfrac{{4ac - {b^2}}}{{2a}}$.
So substituting the values we get minimum value = $\dfrac{{4(1) \times 40 - {{\left( { - 12} \right)}^2}}}{{2 \times 1}} = 8$
Now in the equation $24x - 8 - 9{x^2}$, a=-9, b=24, c=-8.
As $a < 0$ because -9<0, hence using the above mentioned concept at does not have a minimum value and the maximum value is given by $\dfrac{{4ac - {b^2}}}{{2a}}$.
So substituting the values we get the maximum value = $\dfrac{{4(9) \times ( - 8) - {{\left( {24} \right)}^2}}}{{2 \times 9}} = 16$
Note – Whenever we face such types of problems the key concept is to understand whether the parabola formed by the equation given is opening up parabola or opening down parabola, it all depends upon the value of the coefficient of highest power of that equation. Then applying the concept mentioned above we can get the answer.
Complete step-by-step answer:
We have to find the minimum value of ${x^2} - 12x + 40$ and the maximum value of $24x - 8 - 9{x^2}$.
$ \Rightarrow $ Now if we have a quadratic equation of the form ${\text{a}}{{\text{x}}^2} + bx + c = 0$such that $a > 0$ then the minimum value of this quadratic equation is $\dfrac{{4ac - {b^2}}}{{2a}}$at the point x=$\dfrac{b}{{2a}}$ and in this case the maximum value doesn’t exist as the parabola formed is opening upwards and the domain of this equation is R (that is real numbers) thus the max value can go up to infinity.
$ \Rightarrow $ Now if we talk about a quadratic equation of the form ${\text{a}}{{\text{x}}^2} + bx + c = 0$ such that $a < 0$ then the maximum value of this quadratic equation is $\dfrac{{4ac - {b^2}}}{{2a}}$ at point x=$\dfrac{{ - b}}{{2a}}$ and in this case the minimum does not exist as the parabola formed is opening downwards and the domain of this equation is R (that is real numbers) thus the min value can go up to minus infinity.
Now in the equation ${x^2} - 12x + 40$ a=1, b=-12 and c=40
As $a > 0$ because 1>0, hence using the above mentioned concept it does not have a maximum value and the minimum value is given by $\dfrac{{4ac - {b^2}}}{{2a}}$.
So substituting the values we get minimum value = $\dfrac{{4(1) \times 40 - {{\left( { - 12} \right)}^2}}}{{2 \times 1}} = 8$
Now in the equation $24x - 8 - 9{x^2}$, a=-9, b=24, c=-8.
As $a < 0$ because -9<0, hence using the above mentioned concept at does not have a minimum value and the maximum value is given by $\dfrac{{4ac - {b^2}}}{{2a}}$.
So substituting the values we get the maximum value = $\dfrac{{4(9) \times ( - 8) - {{\left( {24} \right)}^2}}}{{2 \times 9}} = 16$
Note – Whenever we face such types of problems the key concept is to understand whether the parabola formed by the equation given is opening up parabola or opening down parabola, it all depends upon the value of the coefficient of highest power of that equation. Then applying the concept mentioned above we can get the answer.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

10 examples of friction in our daily life

