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# The minimum value of ${x^2} - 12x + 40$ and the maximum value of $24x - 8 - 9{x^2}$ is?

Last updated date: 20th Mar 2023
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Hint-In this question we have to find the minimum and maximum value of the given quadratic equations. Check for the coefficient of highest power term to be positive or negative and apply the respective formula for maximum and minimum value of a quadratic equation.

We have to find the minimum value of ${x^2} - 12x + 40$ and the maximum value of $24x - 8 - 9{x^2}$.
$\Rightarrow$ Now if we have a quadratic equation of the form ${\text{a}}{{\text{x}}^2} + bx + c = 0$such that $a > 0$ then the minimum value of this quadratic equation is $\dfrac{{4ac - {b^2}}}{{2a}}$at the point x=$\dfrac{b}{{2a}}$ and in this case the maximum value doesn’t exist as the parabola formed is opening upwards and the domain of this equation is R (that is real numbers) thus the max value can go up to infinity.
$\Rightarrow$ Now if we talk about a quadratic equation of the form ${\text{a}}{{\text{x}}^2} + bx + c = 0$ such that $a < 0$ then the maximum value of this quadratic equation is $\dfrac{{4ac - {b^2}}}{{2a}}$ at point x=$\dfrac{{ - b}}{{2a}}$ and in this case the minimum does not exist as the parabola formed is opening downwards and the domain of this equation is R (that is real numbers) thus the min value can go up to minus infinity.
Now in the equation ${x^2} - 12x + 40$ a=1, b=-12 and c=40
As $a > 0$ because 1>0, hence using the above mentioned concept it does not have a maximum value and the minimum value is given by $\dfrac{{4ac - {b^2}}}{{2a}}$.
So substituting the values we get minimum value = $\dfrac{{4(1) \times 40 - {{\left( { - 12} \right)}^2}}}{{2 \times 1}} = 8$
Now in the equation $24x - 8 - 9{x^2}$, a=-9, b=24, c=-8.
As $a < 0$ because -9<0, hence using the above mentioned concept at does not have a minimum value and the maximum value is given by $\dfrac{{4ac - {b^2}}}{{2a}}$.
So substituting the values we get the maximum value = $\dfrac{{4(9) \times ( - 8) - {{\left( {24} \right)}^2}}}{{2 \times 9}} = 16$