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# The mechanical advantage of a machine is $5$. How much load can it exert for the effort of $2$$kgf$? Verified
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Hint: Mechanical advantage of a machine is the ratio of the output force to the input force. It can also be defined as the ratio between the force exerted by the system and the force applied to the system. The output force or the force exerted by the system is the load in the question and the input force or the force applied to the system is mentioned as effort. Using these relations the value of force exerted by the system that is the load can be computed.

Formula used: $\text{Mechanical advantage}= \dfrac{\text{load}}{\text{effort}}$

Complete step-by-step solution:
The values that have been given to us are;
Mechanical advantage=$5$
and Effort = $2kgf$
The value of load must be determined;
Therefore by using formula, $\text{Mechanical advantage}= \dfrac{\text{load}}{\text{effort}}$
We get, Load= $(5 \times 2)kgf$$= 10kgf$
Therefore from the solution, we get the load value to be equal to $10kgf$