
The mean distance of Mars from the sun is $1.52times$ that of Earth from the Sun. From Kepler’s law of periods, calculate the number of years required for Mars to make one revolution around the Sun.
Answer
527.7k+ views
Hint: In order to answer this question, to calculate the number of years required for Mars to make one revolution around the Sun, we will apply the Kepler’s law of periods equation to find it, and then we will discuss more about the mentioned law.
Complete step by step answer:
According to the Kepler’s law of periods, expressed as a ratio is:
${(\dfrac{{{a_M}}}{{{a_E}}})^3} = {(\dfrac{{{T_M}}}{{{T_E}}})^2}$
Here, $\dfrac{{{a_M}}}{{{a_E}}}$ is the mean distance ratio for the semi-major axis ratio.
and, ${T_E}$ is the number of years for Earth to make one revolution around the Sun.
and we have to calculate the number of years for Mars ( ${T_M}$ ) to make one revolution around the Sun.
$
\Rightarrow {(1.52)^3} = {(\dfrac{{{T_M}}}{{1yr}})^2} \\
\Rightarrow {T_M} = 1.87yr \\
$
Hence, the number of years required for Mars to make one revolution around the Sun is $1.87years$.
Note: Kepler's third and final law is the Law of Periods. The rule shows that the time it takes for a planet to complete its orbit is proportional to its average distance from the sun, using complex mathematical equations.
Complete step by step answer:
According to the Kepler’s law of periods, expressed as a ratio is:
${(\dfrac{{{a_M}}}{{{a_E}}})^3} = {(\dfrac{{{T_M}}}{{{T_E}}})^2}$
Here, $\dfrac{{{a_M}}}{{{a_E}}}$ is the mean distance ratio for the semi-major axis ratio.
and, ${T_E}$ is the number of years for Earth to make one revolution around the Sun.
and we have to calculate the number of years for Mars ( ${T_M}$ ) to make one revolution around the Sun.
$
\Rightarrow {(1.52)^3} = {(\dfrac{{{T_M}}}{{1yr}})^2} \\
\Rightarrow {T_M} = 1.87yr \\
$
Hence, the number of years required for Mars to make one revolution around the Sun is $1.87years$.
Note: Kepler's third and final law is the Law of Periods. The rule shows that the time it takes for a planet to complete its orbit is proportional to its average distance from the sun, using complex mathematical equations.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

The largest wind power cluster is located in the state class 11 social science CBSE

Explain zero factorial class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

What steps did the French revolutionaries take to create class 11 social science CBSE

Which among the following are examples of coming together class 11 social science CBSE

